The bent rod in Fig, a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bcaring at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 05 m „Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m Equations of Equilibrium. The cable tension T, may be obtained directly by summing moments about an axis that passes through points D and A. Why? 00 kg (a) ince the moment arms from the axis to Tg and W are easy to obtain, re can determine this result using a scalar analysis. As shown.Fig. b EMas = 0: Ta(1 m sin 45") - 981 N(O.5 m sin 45") = 0 T, = 490.5 N 05 m 981 N 0.5 m D. (b)

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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The bent rod in Fig, a is supported at A by a journal bearing, at D by
a ball-and-socket joint, and at B by means of cable BC. Using only
one eguitibrium equation, obtain a direct solution for the tension in
cable BC. The bearing at A is capable of exerting force components
only in the z and y directions since it is properly aligned on the shaft.
In other words, no couple moments are required at this support.
05 m
„Free-Body Diagram. As shown in Fig. b, there are six unknowns
05 m
D.
Equations of Equilibrium. The cable tension T, may be obtained
directly by summing moments about an axis that passes through
points D and A. Why?
00 kg
(a)
Since the moment arms from the axis to Tg and W are easy to obtain.
we can determine this result using a scalar analysis. As shown.Fig. b
EMPA = 0: T(1 m sin 45") – 981 N(0.5 m sin 45") = 0
T= 490.5 N
0.5 m
W = 981 N
05 m.
D,
(b)
Transcribed Image Text:The bent rod in Fig, a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one eguitibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 05 m „Free-Body Diagram. As shown in Fig. b, there are six unknowns 05 m D. Equations of Equilibrium. The cable tension T, may be obtained directly by summing moments about an axis that passes through points D and A. Why? 00 kg (a) Since the moment arms from the axis to Tg and W are easy to obtain. we can determine this result using a scalar analysis. As shown.Fig. b EMPA = 0: T(1 m sin 45") – 981 N(0.5 m sin 45") = 0 T= 490.5 N 0.5 m W = 981 N 05 m. D, (b)
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