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The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 1m 0.5 m E .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m D Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kg (a) Since the moment arms from the axis to Tg and W are easy to obtain, we can determine this result using a scalar analysis. As shown,Fig. b EM DA = 0; Tg(1 m sin 45°) – 981 N(0.5 m sin 45°) = 0 Tg = 490.5 N B. 45 0.5 m W = 981NE 0.5 m D. (b)

The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 1m 0.5 m E .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m D Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kg (a) Since the moment arms from the axis to Tg and W are easy to obtain, we can determine this result using a scalar analysis. As shown,Fig. b EM DA = 0; Tg(1 m sin 45°) – 981 N(0.5 m sin 45°) = 0 Tg = 490.5 N B. 45 0.5 m W = 981NE 0.5 m D. (b)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 1 m B. 0.5 m .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m D. Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kg (a) Since the moment arms from the axis toT, and W are easy to obtain, we can determine this result using a scalar analysis. As shown, Fig. b EM DA = 0; TR(1 m sin 45°) - 981 N(0.5 m sin 45°) = 0 ATB TR = 490.5 N u B 45°- 0.5 m W = 981 N rɛ 0.5 m Ip. (b)
Transcribed Image Text:The bent rod in Fig. a is supported at A by a journal bearing, at D by a ball-and-socket joint, and at B by means of cable BC. Using only one equilibrium equation, obtain a direct solution for the tension in cable BC. The bearing at A is capable of exerting force components only in the z and y directions since it is properly aligned on the shaft. In other words, no couple moments are required at this support. 1 m B. 0.5 m .Free-Body Diagram. As shown in Fig. b, there are six unknowns 0.5 m D. Equations of Equilibrium. The cable tension Tg may be obtained directly by summing moments about an axis that passes through points D and A. Why? 100 kg (a) Since the moment arms from the axis toT, and W are easy to obtain, we can determine this result using a scalar analysis. As shown, Fig. b EM DA = 0; TR(1 m sin 45°) - 981 N(0.5 m sin 45°) = 0 ATB TR = 490.5 N u B 45°- 0.5 m W = 981 N rɛ 0.5 m Ip. (b)
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