The beam shown in the figure consists of a W360 x 79 structural steel wide-flange shape [E = 200 GPa; I = 225 × 106 mm¹]. For the loading shown, determine: (a) the reactions at A, B, and C. Enter a positive value for a reaction force that acts upward on the beam, or a negative value for a reaction force that acts downward. (b) the magnitude of the maximum bending stress in the beam. Enter a positive value for the magnitude. Note: Use the tabulated value for the section modulus S from Appendix B directly in the stress calculation. Although S is related to the area moment of inertia I and the cross-section depth d, due to round-off in the tabulated data for S, I, and d, a slightly different answer for the bending stress is obtained using S directly as compared to the result obtained in using I and d. Of course, performing the calculation using either S directly, or using I and d, the answer will likely be within the required tolerance. Assume L₁ = 3.2 m, L₂ = 5.3 m, M = 200 kN-m, and w = 91 kN/m. "| M A (a) Ay = B₁ = Cy= L₁ (b) omax = i i i i B W L₂ kN KN KN MPa X

The beam shown in the figure consists of a W360 x 79 structural steel wide-flange shape [E = 200 GPa; I = 225 × 106 mm¹]. For the loading shown, determine: (a) the reactions at A, B, and C. Enter a positive value for a reaction force that acts upward on the beam, or a negative value for a reaction force that acts downward. (b) the magnitude of the maximum bending stress in the beam. Enter a positive value for the magnitude. Note: Use the tabulated value for the section modulus S from Appendix B directly in the stress calculation. Although S is related to the area moment of inertia I and the cross-section depth d, due to round-off in the tabulated data for S, I, and d, a slightly different answer for the bending stress is obtained using S directly as compared to the result obtained in using I and d. Of course, performing the calculation using either S directly, or using I and d, the answer will likely be within the required tolerance. Assume L₁ = 3.2 m, L₂ = 5.3 m, M = 200 kN-m, and w = 91 kN/m. "| M A (a) Ay = B₁ = Cy= L₁ (b) omax = i i i i B W L₂ kN KN KN MPa X

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.

Question

The beam shown in the figure consists of a W360 x 79 structural steel wide-flange shape [E = 200 GPa; I = 225 × 106 mm¹]. For
the loading shown, determine:
(a) the reactions at A, B, and C. Enter a positive value for a reaction force that acts upward on the beam, or a negative value for a
reaction force that acts downward.
(b) the magnitude of the maximum bending stress in the beam. Enter a positive value for the magnitude. Note: Use the tabulated value
for the section modulus S from Appendix B directly in the stress calculation. Although S is related to the area moment of inertia I and
the cross-section depth d, due to round-off in the tabulated data for S, I, and d, a slightly different answer for the bending stress is
obtained using S directly as compared to the result obtained in using I and d. Of course, performing the calculation using either S
directly, or using I and d, the answer will likely be within the required tolerance.
Assume L₁ = 3.2 m, L₂ = 5.3 m, M = 200 kN-m, and w = 91 kN/m.
"|
M
(a) Ay
B₂
=
=
Cy =
L₁
(b) omax =
i
i
i
i
B
W
L2
kN
Ξ Ξ Ξ
KN
kN
MPa

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