The beam in the figure below is subjected to a load P= 2 kN at its end. Young'smodulus is 210 GPa and the moment of inertia for the beam's cross-section is 5×106mm4.A|--1--|aB|--x₂bPТосCIf a = 1.6 m and b= 0.6 m, determine:a) Reaction value at support A. Positive direction is considered upwards. Enter youranswer in kN to 2 decimal places.

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The beam in the figure below is subjected to a load P=2 kN at its end. Young's modulus is 210 GPa and the moment of inertia for the beam's cross-section is 5×106 mmª. A |×-| a B |-x₂ b P Tuc C If a 1.6 m and b= 0.6 m, determine: a) Reaction value at support A. Positive direction is considered upwards. Enter your answer in kN to 2 decimal places.

The beam in the figure below is subjected to a load P=2 kN at its end. Young's modulus is 210 GPa and the moment of inertia for the beam's cross-section is 5×106 mmª. A |×-| a B |-x₂ b P Tuc C If a 1.6 m and b= 0.6 m, determine: a) Reaction value at support A. Positive direction is considered upwards. Enter your answer in kN to 2 decimal places.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

The beam in the figure below is subjected to a load P= 2 kN at its end. Young's
modulus is 210 GPa and the moment of inertia for the beam's cross-section is 5×106
mm4.
A
|--1--|
a
B
|--x₂
b
P
Тос
C
If a = 1.6 m and b= 0.6 m, determine:
a) Reaction value at support A. Positive direction is considered upwards. Enter your
answer in kN to 2 decimal places.

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