beam in the figure below is subjected to a load P = 3.5 kN at its end. Young’s modulus is 210 GPa and the moment of inertia for the beam’s cross-section is 5×106 mm4. If a = 1.5 m and b = 0.6 m, determine: a) Reaction value at support A. Positive direction is considered upwards. b) moment equation M(x1) in the segment AB, where x1
The beam in the figure below is subjected to a load P = 3.5 kN at its end. Young’s modulus is 210 GPa and the moment of inertia for the beam’s cross-section is 5×106 mm4.
If a = 1.5 m and b = 0.6 m, determine:
a) Reaction value at support A. Positive direction is considered upwards.
b) moment equation M(x1) in the segment AB, where x1 changes from 0 at support A to a at support B. Enter the equation in terms of variables P, a, band x1.
c) moment equation M(x2) in the segment BC, where x2 changes from 0 at point C to b at support B. Enter the equation in terms of variables P, a, band x2.
d) the value of the constant of integration C1
e) the value of the constant of integration C2
f) the value of the constant of integration C3
g) the value of the constant of integration C4
h) the value of displacement at point C
i) the position of maximum displacement in the segment AB
j) the value of maximum displacement in the segment AB
Step by step
Solved in 3 steps with 2 images