The beam shown in Figure 1 supports a distributed load of 20 kN/m. A is a pin support, and B is a roller support. Given E = 200,000 MPa and I = 175 x 106 mm4. Using the principle of virtual work (graphical method) to determine the followings: (a) (b) displacement at C (Ac) in mm slope at B (08) in radian

Q: Question 2 Determine the moment of inertia of the area about the x axis as shown in Figure Q2.…

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Q: Determine the slope and displacement of point B of the steel beam s

A: Modulus of elasticity (E)= 200 GPaMoment of inertia (I)= 60*106 mm4A Beam system given in the figure…

Q: Consider the beam-column shown in the following figure. Determine the deflection y(x). w(x)=w EI, L

A:

Q: The basic differential equation of the elastic curve for a cantilever beam is given by the following…

A: Given the following parameters: L = 120 inches E = 30,000 ksi I = 800 in4 P = 1 kip Initial…

Q: A simply supported beam is shown below. There is a mass (m) of 800 lb placed at midspan m L=30' e…

A: Mass = 800 lbE=29000ksiI=1000 inch4

Q: -2 m -4 m- C 4 m

A:

Q: F2 -300 N F=700 N 60 M. =1500 Nm 2 m 3m or the above diagram, given that F, = 450 N, 8 = 30 degrees…

A:

Q: The rectangular cross-section beam in figure 3b is subjected to a maximum bending moment of 25,000…

A: given beam section:-

Q: Problem 9.3 Consider the truss shown in (Figure 1). Each steel member has a cross-sectional area of…

A:

Q: 5. Two hard rubber blocks are used in an anti-vibration mount to support a small machine as shown in…

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A: Given:Required:Deflection at C

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A: For a non prismatic rod Axial load applied is 80 kN and  100 kN as shown in figureTo determine…

Q: Problem 4 ust. The beam shown below is subjected to the load shown in the figure. Use the…

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Q: A truss (Truss) is subjected to force as shown in the figure below. Try to calculate the vertical…

A: A=200mm2 E=200GPa To find vertical displacement at point C

Q: 3. Rigid member ABD is connected to elastic member CDE as shown. Fo the given loading, what are the…

A: Given Data: E=70 GPa=70×103 N/mm2A=100 mm2CD=0.4m=0.4×1000=400 mm2DE=0.2=0.2×1000=200 mm2

Q: A symmetrical beam of length I has a cantilever support at the left hand end x = 0 and a pin support…

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Q: 1.5 m B -1 m z 2 kN A

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Q: 2. Derive an equation that describes the vertical deflection of the beam, y(x), and also calculate…

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Q: A 240mm diameter circular simply supported beam carries a concentrated load, uniformly distributed…

A: The question is based on the simply supported beam subjected to uniform, varying, and point load.…

Q: Required information Consider the beam given in the figure. Given: X = 0.4 in, E = 30,000 kips/in²,…

A: E = 30,000 kip/in.2I = 240 in.4Determine the support reaction and draw the shear force and bending…

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.