The beam in the figure it’s 6.0 meters long and has a mass of 15kg. A crate with a mass of 30kg hangs from the 5.0 meter mark. Calculate the tension in the wire using the attachment of the beam to the wall as the pivot point. - redraw the figure with all forces acting.
The beam in the figure it’s 6.0 meters long and has a mass of 15kg. A crate with a mass of 30kg hangs from the 5.0 meter mark. Calculate the tension in the wire using the attachment of the beam to the wall as the pivot point. - redraw the figure with all forces acting.
Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter8: Central-force Motion
Section: Chapter Questions
Problem 8.25P
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Rotational Equilibrium And Rotational Dynamics
In physics, the state of balance between the forces and the dynamics of motion is called the equilibrium state. The balance between various forces acting on a system in a rotational motion is called rotational equilibrium or rotational dynamics.
Equilibrium of Forces
The tension created on one body during push or pull is known as force.
Question
The beam in the figure it’s 6.0 meters long and has a mass of 15kg. A crate with a mass of 30kg hangs from the 5.0 meter mark. Calculate the tension in the wire using the attachment of the beam to the wall as the pivot point.
- redraw the figure with all forces acting.
![Conditions of static equilibrium:
ΣΕx = 0
Σ Fx = 0
T = la Fr sin 0
=
L = Iw
Moment of inertia: 1 = [mr₁²
A ring: 1 = MR²
A sphere: 1 = 2/5 MR²
Στον = ΣΤccw
= mvr
KE = ½ 1w²
A disc: 1 = 2 MR²
A rod:
1 = 1/3 ML²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4551f2ef-4c78-4d27-9320-7cb594875026%2Fb8cc0f78-f984-4c62-b150-ee203295e99a%2Fvl8m3cb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Conditions of static equilibrium:
ΣΕx = 0
Σ Fx = 0
T = la Fr sin 0
=
L = Iw
Moment of inertia: 1 = [mr₁²
A ring: 1 = MR²
A sphere: 1 = 2/5 MR²
Στον = ΣΤccw
= mvr
KE = ½ 1w²
A disc: 1 = 2 MR²
A rod:
1 = 1/3 ML²
![45 degrees
30 degrees](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4551f2ef-4c78-4d27-9320-7cb594875026%2Fb8cc0f78-f984-4c62-b150-ee203295e99a%2Fs4mk0i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:45 degrees
30 degrees
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