The beam AB is attached to the wall in the xz plane by a fixed support at A. A force of F = = (-130² + 72.03 + 332k) N is applied to the end of the beam at B. The weight of the beam can be modeled with a uniform distributed load of intensity w = 60.0 N/m acting in the negative z direction along its entire length. Find the support reactions at A. Z с A = A Variable Value 6.10 m 6.00 m 3,20 m a b с b MA= X Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. k) N k) N-m B + F y cc 130 BY NC SA 2016 Eric Davishahl 3+

The beam AB is attached to the wall in the xz plane by a fixed support at A. A force of F = = (-130² + 72.03 + 332k) N is applied to the end of the beam at B. The weight of the beam can be modeled with a uniform distributed load of intensity w = 60.0 N/m acting in the negative z direction along its entire length. Find the support reactions at A. Z с A = A Variable Value 6.10 m 6.00 m 3,20 m a b с b MA= X Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. k) N k) N-m B + F y cc 130 BY NC SA 2016 Eric Davishahl 3+

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

The beam AB is attached to the wall in the xz plane by a
= (-130î + 72.0j + 332k)
fixed support at A. A force of F =
13:18
N is applied to the end of the beam at B. The weight of the
beam can be modeled with a uniform distributed load of
intensity w = 60.0 N/m acting in the negative z direction along
its entire length. Find the support reactions at A.
A =
a
b
Variable Value
с
A
MA=
b
X
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
6.10 m
6.00 m
3.20 m
wamap.org
a
K) N
î+
k) N-m
F
i +
B
cc + O
BY NC SA
2016 Eric Davishahl
y
j+
Ĵ+

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Step 1: State the given data

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Step 2: Vector computation of forces

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Step 3: Force equilibrium equation

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Step 4: Moment at A due to F and W

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