The battery terminal voltage in the figure below is E = 6.90 V and the current I reaches half its maximum value of 4.00 A at t = 0.160 s after the switch is closed.HINTRw(a) Calculate the time constant 7 (in s).0.16X S(b) What is the potential difference (in V) across the inductor at t = 0.160 s?-6.9X V(c) What is the potential difference (in V) across the inductor in the instant after the switch is closed at t = 0?6.90✓ V 4-O- given &9=6.90A=400t=0·160a)еI -Io (1-e² )0.160t0-160en (s)=b)6.90 xc) E. eIIn(*(501X 00.1)= 0.1600.16- (1-05)afhe=>690 xe6-0.166.90 x 1 x 20 t700.160T6.9Zenel=1=/0.160essaa =P&-01 x ²246 = A

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Answered: The battery terminal voltage in the…

The battery terminal voltage in the figure below is &= 6.90 V and the current I reaches half its maximum value of 4.00 A at t= 0.160 s after the switch is closed.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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