The basin of a lake consists of uniform clay with saturated unit weight 19 kN/m3. Calculate the effective stress at a depth of 20 m below ground surface under the lake when the water depth is 5m. The elevation of water in the lake changes throughout the year, it rises to 10 m / 6 m in the rain season. How does this affect the effective stress you have previously calculated? (The ones whose student number is odd will receive the height of rise of the ground water as 10 m, the even ones will receive the height of rise of the ground water as 6 m!!)
The basin of a lake consists of uniform clay with saturated unit weight 19 kN/m3. Calculate the effective stress at a depth of 20 m below ground surface under the lake when the water depth is 5m. The elevation of water in the lake changes throughout the year, it rises to 10 m / 6 m in the rain season. How does this affect the effective stress you have previously calculated? (The ones whose student number is odd will receive the height of rise of the ground water as 10 m, the even ones will receive the height of rise of the ground water as 6 m!!)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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- The basin of a lake consists of uniform clay with saturated unit weight 19 kN/m3. Calculate the effective stress at a depth of 20 m below ground surface under the lake when the water depth is 5m. The elevation of water in the lake changes throughout the year, it rises to 10 m / 6 m in the rain season. How does this affect the effective stress you have previously calculated? (The ones whose student number is odd will receive the height of rise of the ground water as 10 m, the even ones will receive the height of rise of the ground water as 6 m!!)
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