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The base of a three-dimensional figure is bound by the line y = x + 4 on the interval [-3, 1]. Vertical cross sections that are perpendicular to the x-axis are right triangles with a height equal to 4. Algebraically, what is the area of each right triangle? 4 -7654 -3-2-11 1 23 O A = 2(x + 4) O A = (x + 8) O A = 2 (x + 8) O A = (x + 4)

The base of a three-dimensional figure is bound by the line y = x + 4 on the interval [-3, 1]. Vertical cross sections that are perpendicular to the x-axis are right triangles with a height equal to 4. Algebraically, what is the area of each right triangle? 4 -7654 -3-2-11 1 23 O A = 2(x + 4) O A = (x + 8) O A = 2 (x + 8) O A = (x + 4)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Question:** The base of a three-dimensional figure is bound by the line \( y = x + 4 \) on the interval \( [-3, 1] \). Vertical cross sections that are perpendicular to the x-axis are right triangles with a height equal to 4. Algebraically, what is the area of each right triangle? **Graph Explanation:** The graph provided shows the line \( y = x + 4 \), which intersects the y-axis at 4 and has a slope of 1. The interval is from \( x = -3 \) to \( x = 1 \). Various cross sections (represented as shaded regions) are drawn perpendicular to the x-axis, forming right triangles with one leg along the line \( y = x + 4 \) and a constant height of 4 along the y-axis. **Answer Choices:** - \( \circ \quad A = 2(x + 4) \) - \( \circ \quad A = (x + 8) \) - \( \circ \quad A = 2(x + 8) \) - \( \circ \quad A = (x + 4) \)
Transcribed Image Text:**Question:** The base of a three-dimensional figure is bound by the line \( y = x + 4 \) on the interval \( [-3, 1] \). Vertical cross sections that are perpendicular to the x-axis are right triangles with a height equal to 4. Algebraically, what is the area of each right triangle? **Graph Explanation:** The graph provided shows the line \( y = x + 4 \), which intersects the y-axis at 4 and has a slope of 1. The interval is from \( x = -3 \) to \( x = 1 \). Various cross sections (represented as shaded regions) are drawn perpendicular to the x-axis, forming right triangles with one leg along the line \( y = x + 4 \) and a constant height of 4 along the y-axis. **Answer Choices:** - \( \circ \quad A = 2(x + 4) \) - \( \circ \quad A = (x + 8) \) - \( \circ \quad A = 2(x + 8) \) - \( \circ \quad A = (x + 4) \)
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