The bar is now placed on a horizontal, frictionless surface. A constant force of magnitude Fis exerted on the far-right end of the bar, perpendicular to the bar and remains perpendicular, even as the bar rotates. The bar of mass M and length L rotates from position A to position B in a time interval of t. The same constant force of magnitude Fis also exerted on a second bar of mass M/2 and length L/2. 3) Determine how much time, in terms of t, it takes the second smaller bar to rotate from A to B. Clearly show your work or justify your answer.
The bar is now placed on a horizontal, frictionless surface. A constant force of magnitude Fis exerted on the far-right end of the bar, perpendicular to the bar and remains perpendicular, even as the bar rotates. The bar of mass M and length L rotates from position A to position B in a time interval of t. The same constant force of magnitude Fis also exerted on a second bar of mass M/2 and length L/2. 3) Determine how much time, in terms of t, it takes the second smaller bar to rotate from A to B. Clearly show your work or justify your answer.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:IA
The bar is now placed on a horizontal, frictionless surface. A constant force of magnitude Fis exerted on the
far-right end of the bar, perpendicular to the bar and remains perpendicular, even as the bar rotates. The bar
of mass M and length L rotates from position A to position B in a time interval of t.
The same constant force of magnitude Fis also exerted on a second bar of mass M/2 and length L/2.
3) Determine how much time, in terms of t, it takes the second smaller bar to rotate from A to B. Clearly show
your work or justify your answer.

Transcribed Image Text:A solid metal rod of mass M and length L is fixed at its left end and allowed to rotate. When released from rest,
the bar swings through position B. The moment of inertia of a rod rotating about one end is I =ml? where L
is the length of the bar.
1) Derive an expression for the angular acceleration of the bar the instant the bar is released. Express your
answer in terms of M, L and other physical constants.
2) The rod is released and swings from position A through position B. As the rod swings from position A to
position B, its angular acceleration, a, .
increases
decreases
remains the same
Justify your answer.
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