5. An 80 kg gymnast dismounts from a high bar. He starts the dismount at full extension, then tucks to complete a number of revolutions before landing. His moment of inertia when fully extended can be approximated as a rod of length 1.8 m and when in the tuck a rod of half that length. If his rotation rate at full extension is 1.0 rev/s and he enters the tuck when his center of mass is at 3.0 m height moving horizontally to the floor, how many revolutions can he execute if he comes out of the tuck at 1.8 m height?
5. An 80 kg gymnast dismounts from a high bar. He starts the dismount at full extension, then tucks to complete a number of revolutions before landing. His moment of inertia when fully extended can be approximated as a rod of length 1.8 m and when in the tuck a rod of half that length. If his rotation rate at full extension is 1.0 rev/s and he enters the tuck when his center of mass is at 3.0 m height moving horizontally to the floor, how many revolutions can he execute if he comes out of the tuck at 1.8 m height?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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
Transcribed Image Text:5. An 80 kg gymnast dismounts from a high bar. He starts the dismount at full extension, then
tucks to complete a number of revolutions before landing. His moment of inertia when fully
extended can be approximated as a rod of length 1.8 m and when in the tuck a rod of half that
length. If his rotation rate at full extension is 1.0 rev/s and he enters the tuck when his center of
mass is at 3.0 m height moving horizontally to the floor, how many revolutions can he execute if
he comes out of the tuck at 1.8 m height?
High bar
1.8 m
3 m
ANS.
Moment of inertia at full extension, I = 21.6 kg-m^2
Moment of inertia at the tuck I' = 5.4 kg-m^2
Angular velocity at the tuck = 4 rev/sec
Time interval in the tuck = 0.5 sec
i.e. In 0.5 s, he will be able to execute two revolutions at 4.0 rev/s.
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