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The balanced equation is 2N2O5 (g) → 4NO2 (g) + O2 (g) Use the data table to answer the following:  t (s) Concentration of N2O5 (M) 0 1.5 200 0.90 400 0.54 900 0.15   a. What is the rate constant for decomposition of N2O5 ? (Use scientific notation, and proper sig figs, and units)  b. How long will it take for concentration of N2O5 to fall from 0.62 M to 0.10 M? (Use proper units)

The balanced equation is 2N2O5 (g) → 4NO2 (g) + O2 (g) Use the data table to answer the following:  t (s) Concentration of N2O5 (M) 0 1.5 200 0.90 400 0.54 900 0.15   a. What is the rate constant for decomposition of N2O5 ? (Use scientific notation, and proper sig figs, and units)  b. How long will it take for concentration of N2O5 to fall from 0.62 M to 0.10 M? (Use proper units)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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  1. Dinitrogen pentoxide(N2O5) decomposes to form nitrogen dioxide (NO2) and oxygen (O2). This reaction is first order. 

    The balanced equation is 2N2O5 (g) → 4NO2 (g) + O2 (g)

    Use the data table to answer the following: 

    t (s) Concentration of N2O5 (M)
    0 1.5
    200 0.90
    400 0.54
    900 0.15

     

    a. What is the rate constant for decomposition of N2O5 ? (Use scientific notation, and proper sig figs, and units) 

    b. How long will it take for concentration of N2O5 to fall from 0.62 M to 0.10 M? (Use proper units) 

Expert Solution
Step 1: Given data;

Given:-

The given balanced equation is 

2 N subscript 2 O subscript 5 space end subscript left parenthesis g right parenthesis space rightwards arrow space 4 N O subscript 2 left parenthesis g right parenthesis space plus space O subscript 2 left parenthesis g right parenthesis

It is first order reaction, where the rate of the reaction is directly proportional to the concentration of one reactant. 

The data table is as follows;

t(s)Concentration of N subscript 2 O subscript 5 (M)
01.5
2000.90
400054
9000.15
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