The azeotropic condition for the ethanol + n-hexane system at 1 atm (101.3 kPa, 14.696 psia), are as follow: Xethanol-0.332, Xhexane- 0.668, T-331.15 K, P=1 atm. Using the Wilson (two- constants) activity coefficient: a) Calculate A12 and A21. b) Plot the activity-coefficient curves for ethanol versus the composition. c) Discuss about the behaviour of the system using the result in part (b). The temperature variations of A12 and A21 are ignored. The vapor pressures at 331.15 K are Pethanol = 6.26 psia and Prahexane 10.28 psia. In y₁=-In(x₁+ A12x2) A12 A21 x₁ + A12x2 x2 + A21x1, +x2 In y2 = -In(x2 + A21x1) - 11 A12 A21 *₁+A12x2x2 + A21x1,

Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
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The azeotropic condition for the ethanol + n-hexane system at 1 atm (101.3 kPa, 14.696 psia),
are as follow:
Xethanol 0.332, Xhexane- 0.668, T-331.15 K, P=1 atm.
Using the Wilson (two- constants) activity coefficient:
a) Calculate A12 and A21.
b) Plot the activity-coefficient curves for ethanol versus the composition.
c) Discuss about the behaviour of the system using the result in part (b).
The temperature variations of A12 and A21 are ignored.
The vapor pressures at 331.15 K are Paethanol = 6.26 psia and Palhexane 10.28 psia.
In y₁=-In(x₁+ A12x2)
+x21
A21
A12
x₁ + A12x2x2 + A21x1,
XIX)
In 2-In(x2 + A21x1)
A12
(₁
x₁ + A12x2
<-X1
A21
x2 + A21x1.
Transcribed Image Text:The azeotropic condition for the ethanol + n-hexane system at 1 atm (101.3 kPa, 14.696 psia), are as follow: Xethanol 0.332, Xhexane- 0.668, T-331.15 K, P=1 atm. Using the Wilson (two- constants) activity coefficient: a) Calculate A12 and A21. b) Plot the activity-coefficient curves for ethanol versus the composition. c) Discuss about the behaviour of the system using the result in part (b). The temperature variations of A12 and A21 are ignored. The vapor pressures at 331.15 K are Paethanol = 6.26 psia and Palhexane 10.28 psia. In y₁=-In(x₁+ A12x2) +x21 A21 A12 x₁ + A12x2x2 + A21x1, XIX) In 2-In(x2 + A21x1) A12 (₁ x₁ + A12x2 <-X1 A21 x2 + A21x1.
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