The axial assembly consists of a solid 1.06-in.-diameter aluminum alloy [E = 9600 ksi, v = 0.31, a = 14.6 x 10-/°F] rod (1) and a solid 1.48-in.-diameter bronze [E = 12200 ksi, v = 0.18, a = 7.2 x 10-6/°F] rod (2). Assume L1=12 in., L2=27 in. If the supports at A and C are rigid and the assembly is stress free at 1°F, determine: (a) the normal stresses o1,02 in both rods at 135°F (positive if tensile, negative if compressive). (b) the displacement ug of flange B (positive if to the right, negative to the left). (c) the change in diameter Ad of the aluminum rod. B (1) (2) L1 L2 Answers: ( a) σι - i ksi, 02 = i ksi (b) uB = i in. (c) Ad = i in.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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The axial assembly consists of a solid 1.06-in.-diameter aluminum alloy [E = 9600 ksi, v = 0.31, a = 14.6 x 10-/°F] rod (1) and a
solid 1.48-in.-diameter bronze [E = 12200 ksi, v = 0.18, a = 7.2 x 10-6/°F] rod (2). Assume L1=12 in., L2=27 in. If the supports at A and
C are rigid and the assembly is stress free at 1°F, determine:
(a) the normal stresses o1,02 in both rods at 135°F (positive if tensile, negative if compressive).
(b) the displacement ug of flange B (positive if to the right, negative to the left).
(c) the change in diameter Ad of the aluminum rod.
B
(1)
(2)
L1
L2
Answers:
( a) σι -
i
ksi, 02 =
i
ksi
(b) ug =
i
in.
(c) Ad, =
i
in.
Transcribed Image Text:The axial assembly consists of a solid 1.06-in.-diameter aluminum alloy [E = 9600 ksi, v = 0.31, a = 14.6 x 10-/°F] rod (1) and a solid 1.48-in.-diameter bronze [E = 12200 ksi, v = 0.18, a = 7.2 x 10-6/°F] rod (2). Assume L1=12 in., L2=27 in. If the supports at A and C are rigid and the assembly is stress free at 1°F, determine: (a) the normal stresses o1,02 in both rods at 135°F (positive if tensile, negative if compressive). (b) the displacement ug of flange B (positive if to the right, negative to the left). (c) the change in diameter Ad of the aluminum rod. B (1) (2) L1 L2 Answers: ( a) σι - i ksi, 02 = i ksi (b) ug = i in. (c) Ad, = i in.
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