The average time it takes for a molecule to diffuse a distance of x cm is given by t = 2D Assume that the diffusion coefficient of glucose is 5.70 x 10 Round your answer to 3 significant digits. Diffusion time (t) = X -7 cm S 2 where t is the time in seconds and D is the diffusion coefficient. Calculate the time it would take for a glucose molecule to diffuse 18.5 µm.
The average time it takes for a molecule to diffuse a distance of x cm is given by t = 2D Assume that the diffusion coefficient of glucose is 5.70 x 10 Round your answer to 3 significant digits. Diffusion time (t) = X -7 cm S 2 where t is the time in seconds and D is the diffusion coefficient. Calculate the time it would take for a glucose molecule to diffuse 18.5 µm.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Diffusion Time Calculation**
The average time it takes for a molecule to diffuse a distance of \( x \) cm is given by the equation:
\[ t = \frac{x^2}{2D} \]
where:
- \( t \) is the time in seconds.
- \( D \) is the diffusion coefficient.
Assume the diffusion coefficient of glucose is \( 5.70 \times 10^{-7} \, \text{cm}^2/\text{s} \).
**Task:**
Calculate the time it would take for a glucose molecule to diffuse 18.5 µm.
*Instructions:*
- Round your answer to 3 significant digits.
**Input Section:**
- **Diffusion time (\( t \)) =** \(\boxed{\phantom{0}}\) s
*Options:*
- Save for Later
- Submit
**Note:**
Ensure that the distance is converted to the correct unit (cm) before substituting into the formula.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F91f806a5-3485-4560-baf7-fe0d7b379a18%2F97e94a13-6ceb-4416-ba88-998e71c08098%2F7vnpq1v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Diffusion Time Calculation**
The average time it takes for a molecule to diffuse a distance of \( x \) cm is given by the equation:
\[ t = \frac{x^2}{2D} \]
where:
- \( t \) is the time in seconds.
- \( D \) is the diffusion coefficient.
Assume the diffusion coefficient of glucose is \( 5.70 \times 10^{-7} \, \text{cm}^2/\text{s} \).
**Task:**
Calculate the time it would take for a glucose molecule to diffuse 18.5 µm.
*Instructions:*
- Round your answer to 3 significant digits.
**Input Section:**
- **Diffusion time (\( t \)) =** \(\boxed{\phantom{0}}\) s
*Options:*
- Save for Later
- Submit
**Note:**
Ensure that the distance is converted to the correct unit (cm) before substituting into the formula.
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