The average number of words in a romance novel is 64,165and the standard deviation is 17,215. Assume the distributionis normal. Let X be the number of words in a randomlyselected romance novel. Round all answers to 4 decimalplaces where possible.a. What is the distribution of X? X - N(b. Find the proportion of all novels that are between 72,773and 89,988 words.c. The 70th percentile for novels is(Round to the nearest word)d. The middle 80% of romance novels have fromwords tonearest word)words.words. (Round to the On average, indoor cats live to 15 years old with a standarddeviation of 2.2 years. Suppose that the distribution isnormal. Let X = the age at death of a randomly selectedindoor cat. Round answers to 4 decimal places wherepossible.a. What is the distribution of X? X - NOb. Find the probability that an indoor cat dies when it isbetween 15.2 and 17.8 years old.c. The middle 20% of indoor cats' age of death lies betweenwhat two numbers?Low:High:yearsyears

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average number of words in a romance novel is 64,289 and the standard deviation is 17,272. Assume the distribution is normal. Let X be the number of words in a randomly selected romance novel. Round all answers to 4 decimal places where possible.b. Find the proportion of all novels that are between 62,562 and 79,834 words. ________________c. The 85th percentile for novels is words. (Round to the nearest word) ________________d. The middle 70% of romance novels have from _______ words to _______ words. (Round to the nearest word)
Find the z-score that has 70.54% of the distribution's area to its right. Click to view page 1 of the table. Click to view page 2 of the table. O A. - 0.82 В. - 0.54 С. 0.82 D. 0.54
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 70 105 The area of the shaded region is (Round to four decimal places as needed.)
In a normal curve, the percentage of the scores between one and two standard deviations above the mean is approximately __________. Select one: a. 14% b. 50% c. It is impossible to tell. d. 2% Clear my choice
Use the standard normal table to find the z-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. P 25 Click to view page 1 of the table. Click to view page 2 of the table. The z-score that corresponds to P25 is (Round to two decimal places as needed.)
Aу 30+ 25- 20- 15- 10- 5- 2 14 23 2 0+ 48.5 70.5 92.5 114.5 136.5 158.5 x
The frequency distribution was obtained using a class width of 0.5 for data on cigarette tax rates. Use the frequency distribution to approximate the population mean and population standard deviation. Compare these results to the actual mean u = $1.506 and standard deviation o = $1.004. Click the icon to view the frequency distribution for the tax rates. Frequency distribution of cigarette tax rates Tax Rate Frequency 0.00–0.49 7 0.50-0.99 14 1.00–1.49 7 1.50–1.99 2.00–2.49 5 2.50–2.99 5 3.00–3.49 3.50–3.99 1 4.00-4.49 1
Use the sample statistics to test the claim that the mean score on a final exam is more than 78. x¯=81x¯=81 s=10s=10 n=41
Use R to determine whether the mean population by census tract in 2016 is higher than the mean population by census tract in 2012. We also know that in each year, the number of residents by census tract in the State of Maryland follows a normal distribution, and the variance in the number of residents within the State of Maryland is the same for different years. POP2012: 3166, 2210, 3784, 2472, 3157, 4046, 4536, 4084, 7612, 3536, 3187, 2696, 4003, 3889, 2319, 2559, 3051, 4871, 4052, 6767, 6243, 6637, 4066, 3212, 3586, 4835, 2679, 2893, 8868, 4989, 5407, 4703, 4111, 3549, 4974, 3153, 3972, 1920, 2039, 1493, 5510, 4730, 6220, 3478, 5012, 5026, 4350, 3788, 2601, 3492, 1515, 4231, 4344, 4094, 4075, 3210, 4576, 3663, 4388, 4402, 2969, 3418, 3583, 3793, 2284, 3251, 4026, 2714, 5506, 3730, 3913, 3853, 5914, 6073, 3569, 3022, 4801, 5119, 2710, 6259, 3859, 2912, 3611, 3437, 2149, 2414, 3858, 3888, 5878, 1678, 6040, 3779, 2225, 3248, 2039, 2459, 4316, 3712, 4916, 3331, 5079, 2047, 3249, 3579,…
The numbers of courses taught per semester by a random sample of university professors are shown in the histogram. Make a frequency distribution for the data. Then use the table to estimate the sample mean and the sample standard deviation of the data set. Make a frequency distribution for the data. X 1 3 f Number of professors 25- 20- 15- 10- 4 20 23 15 1 2 3 4 Number of courses taught per semester
Find the mean of the data summarized in the given frequency distribution. The test scores of 40 students are summarized in the frequency distribution below. Find the mean score. Score Students 50-59 60-69 70-79 80-89 90-99 57728 12
Assume that the readings on the thermometers are normally distributed with a mean of 0° and standard deviation of 1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P34, the 84th percentile. This is the temperature reading separating the bottom 84% from the top 16%. Click to view page 1 of the table. Click to view page 2 of the table. Which graph represents P ? Choose the correct graph below. 84 A. В. OC. D. Ay X The temperature for P84 is approximately (Round to two decimal places as needed.)

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