The average number of moves a person makes in his or her lifetime is 12 and the standard deviation is 3.3. Assume that the sample is taken from a large population and the correction factor can be ignored. Round the final answers to four decimal places and intermediate z value calculations to two decimal place Part 1 of 3 Find the probability that the mean of a sample of 25 people is less than 10. P(X<10)= Part 2 of 3 X Part 3 of 3 Find the probability that the mean of a sample of 25 people is greater than 10. P(X>10)- X S X S Find the probability that the mean of a sample of 25 people is between 11 and 12. P(11

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The problem presented involves calculating probabilities related to the mean number of moves a person makes in their lifetime, using statistical concepts. Here's a detailed transcription suitable for an educational website:

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### Statistical Probability and Sample Means

The average number of moves a person makes in his or her lifetime is 12, with a standard deviation of 3.3. This scenario assumes the sample is taken from a large population, and the correction factor can be ignored. Final answers should be rounded to four decimal places, and intermediate z value calculations should be rounded to two decimal places.

#### Part 1 of 3
**Objective:** Find the probability that the mean of a sample of 25 people is less than 10.

\[ P(\overline{X} < 10) = \boxed{\phantom{5}} \]

---

#### Part 2 of 3
**Objective:** Find the probability that the mean of a sample of 25 people is greater than 10.

\[ P(\overline{X} > 10) = \boxed{\phantom{5}} \]

---

#### Part 3 of 3
**Objective:** Find the probability that the mean of a sample of 25 people is between 11 and 12.

\[ P(11 < \overline{X} < 12) = \boxed{\phantom{5}} \]

---

### Explanation:

These tasks involve the use of the normal distribution and the concept of the sampling distribution of the sample mean. With a known sample size (\(n = 25\)), the mean (\(\mu = 12\)), and the standard deviation (\(\sigma = 3.3\)), you can calculate the standard error and use the z-score formula to find the probabilities:

1. **Calculate the standard error (SE):**
   \[
   SE = \frac{\sigma}{\sqrt{n}}
   \]

2. **Use the z-score formula:**
   \[
   z = \frac{\overline{X} - \mu}{SE}
   \]

These calculations lead to the probabilities based on the z-scores from the standard normal distribution tables.

---
Transcribed Image Text:The problem presented involves calculating probabilities related to the mean number of moves a person makes in their lifetime, using statistical concepts. Here's a detailed transcription suitable for an educational website: --- ### Statistical Probability and Sample Means The average number of moves a person makes in his or her lifetime is 12, with a standard deviation of 3.3. This scenario assumes the sample is taken from a large population, and the correction factor can be ignored. Final answers should be rounded to four decimal places, and intermediate z value calculations should be rounded to two decimal places. #### Part 1 of 3 **Objective:** Find the probability that the mean of a sample of 25 people is less than 10. \[ P(\overline{X} < 10) = \boxed{\phantom{5}} \] --- #### Part 2 of 3 **Objective:** Find the probability that the mean of a sample of 25 people is greater than 10. \[ P(\overline{X} > 10) = \boxed{\phantom{5}} \] --- #### Part 3 of 3 **Objective:** Find the probability that the mean of a sample of 25 people is between 11 and 12. \[ P(11 < \overline{X} < 12) = \boxed{\phantom{5}} \] --- ### Explanation: These tasks involve the use of the normal distribution and the concept of the sampling distribution of the sample mean. With a known sample size (\(n = 25\)), the mean (\(\mu = 12\)), and the standard deviation (\(\sigma = 3.3\)), you can calculate the standard error and use the z-score formula to find the probabilities: 1. **Calculate the standard error (SE):** \[ SE = \frac{\sigma}{\sqrt{n}} \] 2. **Use the z-score formula:** \[ z = \frac{\overline{X} - \mu}{SE} \] These calculations lead to the probabilities based on the z-scores from the standard normal distribution tables. ---
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