The average number of miles (in thousands) that a car's tire will function before needingreplacement is 64 and the standard deviation is 18. Suppose that 18 randomly selected tires aretested. Round all answers to 4 decimal places where possible and assume a normal distribution.a. What is the distribution of X? X - N( 64b. What is the distribution of ? - N( 64میc. If a randomly selected individual tire is tested, find the probability that the number of miles (inthousands) before it will need replacement is between 63.4 and 68.3.d. For the 18 tires tested, find the probability that the average miles (in thousands) before needof replacement is between 63.4 and 68.3.e. For part d), is the assumption that the distribution is normal necessary? No Yes

Step 1: Given Data: Mean (μ) = 64 (in thousands of miles)Standard deviation (σ) = 18 (in thousands…

Answered: The average number of miles (in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average American man consumes 9.7 grams of sodium each day. Suppose that the sodium consumption of American men is normally distributed with a standard deviation of 1 grams. Suppose an American man is randomly chosen. Let X = the amount of sodium consumed. Round all numeric answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N Note: this shows 2 blank spots for answers
The mean is 146 and the standard deviation is 35. A score of 41 is how many z-scores below the mean?
In a population distribution a score of x equals 28 corresponds to z equals -1.00 and a score of x - 34 corresponds to z equals - 0.50 find the mean and standard deviation for the population
The IQ's in a certain population are normally distributed with a mean score of 104 and a standard deviation of 14. If we select a person at random from this population, find the probability that their IQ will be: 1. Find the 67th percentile of IQ's in this population. 2. Find the 20 The percentile of IQ's in this population 3. Find the IQR of IQ's in this population.
The average amount of money spent for lunch per person in the college cafeteria is $6.24 and the standard deviation is $2.05. Suppose that 6 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible.What is the distribution of ¯x?
Use the formula to find the standard error of the distribution of differences in sample means, x⎯⎯1−x⎯⎯2x¯1-x¯2.Samples of size 40 from Population 1 with mean 3.7 and standard deviation 1.9 and samples of size 40 from Population 2 with mean 1.9 and standard deviation 1.2Round your answer for the standard error to two decimal places.standard error = Enter your answer in accordance to the question statement
The average grade for an exam is 74, the standard deviation is 7 and the grades are curved to follow a normal distribution. Find the probability that a student will get a grade from 81 to 88 Select one: O a. 0.451 b. 0.612 O c. 0.1359 O d. 0.561
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1463 and the standard deviation was 314. The test scores of four students selected at random are 1870, 1220, 2190, and 1340. Find the z-scores ← that correspond to each value and determine whether any of the values are unusual. F1 The z-score for 1870 is (Round to two decimal places as needed.) The z-score for 1220 is. (Round to two decimal places as needed.) The z-score for 2190 is (Round to two decimal places as needed.) The z-score for 1340 is. (Round to two decimal places as needed.) Which values, if any, are unusual? Select the correct choice below and, if necessary, fill in the answer box within your choice. OA. The unusual value(s) is/are. (Use a comma to separate answers as needed.) OB. None of the values are unusual. F2 80 F3 000 000 F4 F5 ^ MacBook Air F6 & A D F7 * DII F8 DD F9 ) J 운 F10 I a F11 + Next F12 delete
In a test, the average of the grades is 80 and the standard deviation is 5. John's grade is 70, so his grade is standard deviations the average. 2 below 10 --------- below 70 above equal to
Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 89 and 121. Click to view page 1 of the table. Click to view page 2 of the table. Standard Normal Table (Page 2) The probability that a randomly selected adult has an IQ between 89 and 121 is (Type an integer or decimal rounded to four decimal places as needed.) POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 5478 .5517 .5557 .5596 ,5636 ,5675 .5714 .5753 0.2 .5793 .5832 5871 5910 .5948 .5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.5 .6915 6950 .6985 7019 .7054 .7088 7123 7157 .7190 .7224 0.6 .7257 .7291 7324 7357 7389 7422 7454 7486…
The mean height of an adult giraffe is 18 feet. Suppose that the distribution is normally distributed with standard deviation 1 feet. Let X be the height of a randomly selected adult giraffe. Round all answers to 4 decimal places where possible.a. What is the distribution of X? ~ N( , )b. What is the median giraffe height? ________ ft.c. What is the Z-score for a giraffe that is 20 foot tall? _________
Assume that IQ scores are normally distributed, with a mean of 100 points and a standard deviation of 14 points. If 50 people are chosen at random, what is the probability that the sample mean of IQ scores will be between 98 and 102?P(98 ≤ x ≤ 102) = ?

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