The average THC content of marijuana sold on the street is 9%. Suppose the THC content is normallydistributed with standard deviation of 1%. Let X be the THC content for a randomly selected bag ofmarijuana that is sold on the street. Round all answers to 4 decimal places where possible,a. What is the distribution of X? X - Nb. Find the probability that a randomly selected bag of marijuana sold on the street will have a THCcontent greater than 9.1.c. Find the 67th percentile for this distribution.

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Answered: The average THC content of marijuana…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A final exam in Reindeer Research Studies has a mean of 60 and a standard deviation of 5. If 25 students are randomly selected, find the probability that the mean of their test scores less than 65. P(x < 65) = P(z < (Enter your answer as a percent accurate to 1 decimal place, do not enter the "%" sign). Shade: Left of a value v. Click and drag the arrows to adjust the values. -2 fI -1 1.5 -4 -3 2 3 4
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P25, the 25-percentile. This is the temperature reading separating the bottom 25% from the top 75%.P25 = °C(Round answer to three decimal places)
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P61, the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%. P61 = (Round answer to three decimal places)
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P89, the 89-percentile. This is the temperature reading separating the bottom 89% from the top 11%. P89 = *C
the mean is 146, and standard deviation is 35. A score of 181 is how many z-scores above the mean?
Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an 1Q less than 129. Click to view page 1 of the table. Click to view page 2 of the table. The probability that a randomly selected adult has an IQ less than 129 is (Type an integer or decimal rounded to four decimal places as needed.)
Assume that the readings on the thermometers are normally distributed with a mean of 0 degrees and standard deviation of 1.00degrees C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to Upper P 95 , the 95 th percentile. This is the temperature reading separating the bottom 95 % from the top 5 %.
Assume that the readings on the thermometers are normally distributed with a mean of 0°and standard deviation of1.00°C. A thermometer is randomly selected and tested. Draw a sketch and find the temperature reading corresponding to P91,the 91stpercentile. This is the temperature reading separating the bottom 91% from the top 9%.
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P26, the 26-percentile. This is the temperature reading separating the bottom 26% from the top 74%.P26 = °C(Round answer to three decimal places)
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P29, the 29-percentile. This is the temperature reading separating the bottom 29% from the top 71%.P29 = °C(Round answer to three decimal places)
Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P61, the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%. P61 = °C Submit Question
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P80, the 80-percentile. This is the temperature reading separating the bottom 80% from the top 20%.P80 = °C

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