The average commuting time from home to work of 64 randomly chosen people is 35 minutes with a standard deviation of 16 minutes. What is the value of for a 95% confidence interval? Round your answer to three decimal places e.g. 4.123. O 1.998 O 0.397 O 0.490 O 0.510 O 1.669
Q: Construct a 90% confidence interval for the true mean fat content of all the packages of ground…
A: The sample size is 8, the sample mean is 14, and sample variance is 2.
Q: How many more Tweets are students at Hempstead High School sending in 2017 than in 2012? The table…
A: If an interval is proposed as an estimate of the unknown parameter, then it is interval estimation.…
Q: Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 23.…
A: It is given that the sample size is 23 and the confidence level is 0.90.
Q: How large a sample should be selected to provide a 90% confidence interval with a margin of error of…
A: Given,population standard deviation(σ)=60margin of error(E)=9α=1-0.90=0.1α2=0.05Z0.05=1.645
Q: You may need to use the appropriate appendix table or technology to answer this question. LSAT test…
A: We have given that, X be the random variable from normal distribution with mean (μ) = 156 and…
Q: Which of the following would increase the width of a confidence interval for a population mean?
A:
Q: A confidence interval was found to be (2.4, 7.9). What was the point estimate? O A. 5.27 O B. 5.2 O…
A: Given confidence interval is (2.4 , 7.9)Upper limit =7.9Lower limit =2.4
Q: Construct a confidence interval for the mean of the paired differences for the two populations with…
A: Solution: From the given information, n=32, d-bar=1.358, α=0.05 and sd=0.635.
Q: Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 4. (Round…
A: Obtain the critical value of t for a 0.95 confidence level when the sample is 4. Obtain the degrees…
Q: You measure 28 dogs' weights, and find they have a mean weight of 71 ounces. Assume the population…
A:
Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error…
A:
Q: Find the sample size required to estimate the mean IQ of all college students. Assume we want a 99…
A: From the given information, σ=15 and E=2.
Q: Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made…
A: Given that, Sales personnel for Skillings Distributors submit weekly listing the customer contacts…
Q: You measure 37 dogs' weights, and find they have a mean weight of 70 ounces. Assume the population…
A:
Q: A random sample of 91 observations produced a mean x = 25.7 and a standard deviation s = 2.4. a.…
A:
Q: The weights of 5 squash (in pounds) are 10, 17, 17.5, 18.5, and 19.5. The sample weights have a mean…
A:
Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…
A: Population standard deviation, sigma is 50. The z-critical value for 95% confidence interval is…
Q: Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 23.…
A:
Q: Among those taking the Graduate Record Exam, 18 people are randomly selected. This group had a mean…
A: The point estimate for the population mean for the GRE test is 550. The margin of error is, Thus,…
Q: n=10, x=13.0, s=4.5. Using StatCrunch, find a 95% confidence interval for the mean. A. (9.80, 16.20)…
A: The random sample of size, The sample mean, The sample standard deviation, The confidence interval…
Q: na random sample of twelve people, the mean driving distance to Work Was 24. ormally distributed and…
A: Given Xbar=24.7 S=5.5
Q: You may need to use the appropriate appendix table or technology to answer this question. Sales…
A:
Q: We would like to construct a 90% confidence interval for the mean, based on a sample of 35…
A: Given data,Sample size n=35sample mean x=11sample sd is s=3.2Construct a 90% CI?
Q: Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 8. (Round…
A:
Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…
A: Givenconfidence interval(c)=95%margin of error(E)=8standard deviation(σ)=10
Q: 15 people were asked to measure their pulse rates after completing a 3 km run. The sample data are…
A: Step-by-step procedure to obtain the 98% confidence interval for them mean of the population using…
Q: A random sample of 100 observations from a population possesses a mean equal to 83.2 and a standard…
A: Given Data: n=100 sample mean=83.2 sample standard deviation=6.4 As population variance is not…
Q: ow large a sample should be selected to provide a 95% confidence interval with a margin of error of…
A: Given Information: Confidence level = 95% = 0.95 Margin of Error = 5 Population standard deviation…
Q: A researcher wants to estimate the mean blood cholesterol level of young men ages 15-25 with a…
A: It is given that the confidence level is 0.8462, the standard deviation is 45, and the margin of…
Q: Suppose someone wanted an 75%-confidence interval. What value of z should they use? Choose the…
A: Level of significance ɑ=0.25
Q: A recent survey asked 47 randomly selected employees how long they had been employed at their…
A: Given Data: x¯=4.6s=2.3n=47 1. Point estimate Point estimate=4.6
Q: A test has a mean score of 150 and a standard deviation of 12. Soores are normaly distributed. What…
A: Given that, μ=150 and σ=12 We have to find, P(133<X<164)
Q: Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 6. (Round…
A: It is given that the sample size is 6.
Q: A recent survey of 6 social networking sites has a mean of 15.65 million visitors for a specific…
A: A recent survey of 6 social networking sites has a mean of 15.65 million visitors for a specific…
Q: 2. In a simple random sample of 125 households, the sample mean number of personal computers was…
A:
Q: In a random sample of eleven people, the mean driving distance to work was 25.7 miles and the…
A: Given that, n=no. of sample=11 x=mean=25.7 s=standard deviation=4.1 Confidence interval is 99%
Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…
A:
Q: Past experience has indicated that the breaking strength of yarn used in manufacturing drapery…
A: Given:
Q: How large a sample should be selected to provide a 95 confidence interval with a margin of error of…
A: From the provided information,Confidence level = 95%Margin of error (E) = 4Population standard…
Q: 2. In a simple random sample of 125 households, the sample mean number of personal computers was…
A: It is given that the mean is 1.18 and the population standard deviation is 0.33.
Q: You measure 37 watermelons' weights, and find they ha population standard deviation is 10 ounces.…
A: Given: n = 37 x=51σ=10 The value of z at 95% confidence level is 1.96, which can be obtained by…
Q: Last Wednesday, a random sample of 16 students were surveyed to find how long it takes to walk from…
A:
Q: A random sample of 56 fluorescent light bulbs has a mean life of 645 hours and assume that the…
A: The given data is as follows:Sample size, Sample mean, Population standard deviation,
Q: You measure 25 randomly selected textbooks' weights, and find they have a mean weight of 39 ounces.…
A: Here, mean is 39 and standard deviation is 11.2. Sample number is 25. We will use one sample z…
Q: A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to…
A: Population standard deviation()=1.3Margin of error(E)=0.06
Q: Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 4. (Round…
A: Given information- Confidence level, c = 0.95 So, significance level, α = 0.05 Sample size, n = 4…
Q: construct a 99% confidence interval of the population proportion using the given information.…
A:
Q: You measure 31 turtles' weights, and find they have a mean weight of 53 ounces. Assume the…
A:
Step by step
Solved in 2 steps with 2 images
- You measure 48 textbooks' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 8.3 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places AFWThis question is confusing meYou measure the lifetime of a random sample of 64 tires of a certain brand. The sample mean is = 50 months. Suppose that the lifetimes for tires of this brand follow a Normal distribution, with unknown mean and standard deviation = 3.79 months A 99% confidence interval for is: a. 40.2 to 59.8. b. 48.39 to 51.61. c. 48.78 to 51.22. d. 49.8 to 50.2.
- How large a sample should be selected to provide a 95% confidence interval with a margin of error of 7? Assume that the population standard deviation is 50. Round your answer to next whole number.A marine biologist would like to estimate the mean weight of all mahi mahi on the Treasure Coast, using a 99% confidence interval. The standard deviation of the weights of all mahi mahi on the Treasure Coast is known to be 8.2 pounds. How large a sample of mahi mahi should the marine biologist select so that the estimate is within 0.88 pounds of the true population mean. Round the solution up to the nearest whole number. n=From a sample of 30 graduate students, the mean number of months of work experience prior to entering an MBA program was 33.93. The national standard deviation is known to be 17 months. What is a 90% confidence interval for the population mean? A 90% confidence interval for the population mean is || | (Use ascending order. Round to two decimal places as needed.) View an Example Get More Help - Clear All Check Answs Help Me Solve This earch acer
- Suppose that textbook weights are normally distributed. You measure 30 textbooks' weights, and find they have a mean weight of 65 ounces. Assume the population standard deviation is 11.6 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight. Round answers to 2 decimal places.? ? ?Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 17. (Round your answer to three decimal places.)Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 25. (Round your answer to three decimal places.)