2. In a simple random sample of 125 households, the sample mean number of personal computers was 1.18. Assume the population standard deviation is 0.33. a. Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. nd Ince the year 2000 for true mean length of all for decimal place. b. What calculator function did you use to create this interval? (T-interval, Z-interval, etc.) c. If the sample size were 95 rather than 125, would the margin of error be larger or smaller than the result in part (a)? Interpret inte val in terms of d. If the confidence levels were 99% rather than 80%, would the margin of error be larger or smaller than the result in part (a)?

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Please answer question 2 parts c and d
2-interval, etc)
2. In a simple random sample of 125 households, the sample mean number of personal computers was
1.18. Assume the population standard deviation is 0.33.
a. Construct an 80% confidence interval for the mean number of personal computers. Round the
answer to at least two decimal places.
age movies ade since the
.5
true mean length
st ane decimal place.
e
b. What calculator function did you use to create this interval? (T-interval, Z-interval, etc.)
c. If the sample size were 95 rather than 125, would the margin of error be larger or smaller than the
result in part (a)?
Interval in ter
d. If the confidence levels were 99% rather than 80%, would the margin of error be larger or smaller
than the result in part (a)?
3. A survey of 100 Americans found that 68% said they find it hard to buy holiday gifts that convey their
true feelings. How large a sample is needed to estimate the true proportion of Americans who
struggle with buying gifts within 2% with 90% confidence? (Include Units!)
and their men legth is 129
is actually les the the
contradict thi c
Transcribed Image Text:2-interval, etc) 2. In a simple random sample of 125 households, the sample mean number of personal computers was 1.18. Assume the population standard deviation is 0.33. a. Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. age movies ade since the .5 true mean length st ane decimal place. e b. What calculator function did you use to create this interval? (T-interval, Z-interval, etc.) c. If the sample size were 95 rather than 125, would the margin of error be larger or smaller than the result in part (a)? Interval in ter d. If the confidence levels were 99% rather than 80%, would the margin of error be larger or smaller than the result in part (a)? 3. A survey of 100 Americans found that 68% said they find it hard to buy holiday gifts that convey their true feelings. How large a sample is needed to estimate the true proportion of Americans who struggle with buying gifts within 2% with 90% confidence? (Include Units!) and their men legth is 129 is actually les the the contradict thi c
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