The average bond enthalpy for C-H is 413 kJ mol.413 kJ mol- of energy is required to break a mole of CH into atoms: CH(9) C(g) + H(g), AH =413 kJ molUsing this information, and your answer from Part A, calculate the enthalpy change of the reaction from Part B. That is, calculate the energy required to break only the carbon-carbon bonds in benzene. Express your answer to four significant figures and include the appropriate units. > View Available Hint(s) HA AH = Value Units

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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From part A ∆H°r=5532.1KJ/mol

From part B C6H6(g)->6CH(g)

 

Part C
The average bond enthalpy for C-H is 413 kJ mol. 413 kJ mol of energy is required to break a mole of CH into atoms:
CH(9) C(9) + H(9),
enthalpy change of the reaction from Part B. That is, calculate the energy required to break only the carbon-carbon bonds
AH = 413 kJ mol-Using this information, and your answer from Part A, calculate the
in benzene.
Express your answer to four significant figures and include the appropriate units.
• View Available Hint(s)
HA
AH =
Value
Units
Transcribed Image Text:Part C The average bond enthalpy for C-H is 413 kJ mol. 413 kJ mol of energy is required to break a mole of CH into atoms: CH(9) C(9) + H(9), enthalpy change of the reaction from Part B. That is, calculate the energy required to break only the carbon-carbon bonds AH = 413 kJ mol-Using this information, and your answer from Part A, calculate the in benzene. Express your answer to four significant figures and include the appropriate units. • View Available Hint(s) HA AH = Value Units
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