The asymmetric simple truss is loaded as shown. Determine the reactions at A and D. Neglect the weight of the structure compared with the applied loads. Is the knowledge of the size of the structure necessary? 4L A 60° Answers: Ay= Dy= Dx= i i i B 3L y T I C 60° 60° 3L L L L 30° 2L D

The asymmetric simple truss is loaded as shown. Determine the reactions at A and D. Neglect the weight of the structure compared with the applied loads. Is the knowledge of the size of the structure necessary? 4L A 60° Answers: Ay= Dy= Dx= i i i B 3L y T I C 60° 60° 3L L L L 30° 2L D

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

The
asymmetric simple truss is loaded as shown. Determine the reactions at A and D. Neglect the weight of the structure compared with
the applied loads. Is the knowledge of the size of the structure necessary?
4L
A
60°
Answers:
Ay =
i
Dy=
Dx= 1
i
B
3L
60° 60°
E
y
T
I
C 3L
L
L
L
30°
2L
D

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Structural
Y = 94 A = 2 B = 1 C = 9
The pin-connected structure consists of a rigid bar ABCD and two axial members. Bar (1) is bronze [E = 116 GPa] with a cross-sectional area of A₁ = 550 mm². Bar (2) is an aluminum alloy [E = 71 GPa] with a cross-sectional area of A₂ = 290 mm². A concentrated load of P = 62 kN acts on the structure at D. Assume L₁=800 mm., L2=560 mm., a-590 mm., b=430 mm., and c=1160 mm. Determine: (a) the normal stresses 01, 02 in both bars (1) and (2). (b) the downward deflection vp of point D on the rigid bar. a b Answers: (a) σ₁ = (b) VD = i (1) L₁ L2 (2) A B MPa, 0₂ = mm. D MPa