The Arrhenius equation is k = Ae Ea/RT. The intercept, b of a plot of In k vs. 1/T is equal to -Ea/R In A Ok

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Chapter1: Chemical Foundations
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**The Arrhenius Equation and its Intercept**

The Arrhenius equation is represented as:

\[ k = Ae^{-E_a/RT} \]

where:
- \( k \) is the rate constant,
- \( A \) is the pre-exponential factor,
- \( E_a \) is the activation energy,
- \( R \) is the gas constant,
- \( T \) is the temperature in Kelvin.

In the context of the Arrhenius equation, when plotting \(\ln k\) versus \(1/T\), the intercept, \( b \), is equal to:

**Options:**
- ⭕ \(-k\)
- ⭕ \(-E_a/R\)
- ⭕ \(\ln A\)  *(Correct Answer)*
- ⭕ \(k\)

This plot typically presents a straight line where the slope is \(-E_a/R\) and the y-intercept is \(\ln A\). The correct answer for the intercept \( b \) is \(\ln A\).
Transcribed Image Text:**The Arrhenius Equation and its Intercept** The Arrhenius equation is represented as: \[ k = Ae^{-E_a/RT} \] where: - \( k \) is the rate constant, - \( A \) is the pre-exponential factor, - \( E_a \) is the activation energy, - \( R \) is the gas constant, - \( T \) is the temperature in Kelvin. In the context of the Arrhenius equation, when plotting \(\ln k\) versus \(1/T\), the intercept, \( b \), is equal to: **Options:** - ⭕ \(-k\) - ⭕ \(-E_a/R\) - ⭕ \(\ln A\) *(Correct Answer)* - ⭕ \(k\) This plot typically presents a straight line where the slope is \(-E_a/R\) and the y-intercept is \(\ln A\). The correct answer for the intercept \( b \) is \(\ln A\).
Expert Solution
Basic

The Arrhenius equation is 

K = Ae-Ea/RT 

By the Arrhenius equation we get the relation between the Rate Constant (K) and the temperature (T) 

As the temperature increases the rate Constant of the reaction Increases .

When we rearrange the Arrhenius equation , then we can solve the above question .

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