The armature of a 6- pole, lap- wound d.c.shunt motor takes a current of 350. A at a speed of 400 r.p.m.The flux / pole is 75 mWb and the number of armature conductors is 1200. Calculate the brake horsepower if 3% of the torque is lost in function, windage and iron losses.

The armature of a 6- pole, lap- wound d.c.shunt motor takes a current of 350. A at a speed of 400 r.p.m.The flux / pole is 75 mWb and the number of armature conductors is 1200. Calculate the brake horsepower if 3% of the torque is lost in function, windage and iron losses.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Winding and Constructions

Alternating Current (AC) winding is generally of the 3-phase type due to the inherent advantages of the 3-phase machine. Armature coils must be connected to the yield balance (equivalent in magnitude and 2/3 of the series phase difference of the rod) 3-phase electromotive forces (emf). The armature should be divided into step-bands to start with slots around the perimeter.In the construction of AC machines, the frame is used as an external protective shield to protect it from environmental conditions. The frame also serves as the outer perimeter, allowing the interior to be easily placed. The static state section of the devices is the stator winding attached stator.

Question

The armature of a 6-pole, lap-wound D.C. shunt motor takes a current of 350 A at a speed of 400 r.p.m. The flux per pole is 75 mWb, and the number of armature conductors is 1200. Calculate the brake horsepower if 3% of the torque is lost in friction, windage, and iron losses.

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