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The approximate empirical expression for variation of molar heat capacity at constant pressure Cpm with temperature is given by Cpm a + bT + T2 [4] Calculate the change in molar enthalpy AH, when the given gas is heated from 25 °C to 500 °C using the expression above. The constants a, b, and c are available in Table 2B.1. AT= 500 – 25 = 475K for Br2 : a-37.32 b=0.50×10³K! c=-1.26×10°K?

The approximate empirical expression for variation of molar heat capacity at constant pressure Cpm with temperature is given by Cpm a + bT + T2 [4] Calculate the change in molar enthalpy AH, when the given gas is heated from 25 °C to 500 °C using the expression above. The constants a, b, and c are available in Table 2B.1. AT= 500 – 25 = 475K for Br2 : a-37.32 b=0.50×10³K! c=-1.26×10°K?

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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  • Compare DHm from (1) and (2) and comment.
The approximate empirical expression for variation of molar heat capacity at constant pressure Cm with temperature is given by Cp.m = a + bT + T2 [4] Calculate the change in molar enthalpy AHm when the given gas is heated from 25 °C to 500 °C using the expression above. The constants a, b, and c are available in Table 2B.1. AT= 500 – 25 = 475K for Br2 : a-37.32 b=0.50×10³K! c=-1.26x10 K? [5] Evaluate Cp.m at 298 K using the above expression. What is AHm using this constant value of Cp.m? [6] Compare AHm from (1) and (2) and comment.
Transcribed Image Text:The approximate empirical expression for variation of molar heat capacity at constant pressure Cm with temperature is given by Cp.m = a + bT + T2 [4] Calculate the change in molar enthalpy AHm when the given gas is heated from 25 °C to 500 °C using the expression above. The constants a, b, and c are available in Table 2B.1. AT= 500 – 25 = 475K for Br2 : a-37.32 b=0.50×10³K! c=-1.26x10 K? [5] Evaluate Cp.m at 298 K using the above expression. What is AHm using this constant value of Cp.m? [6] Compare AHm from (1) and (2) and comment.
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