% transmittance alkyl halide 4000 5.0 4.5 3500 1 (sextet) 4.0 CH (sp³) 3000 3.5 Molecule 5 2500 3.0 2000 wavenumber (cm-¹) 2.5 8 (ppm) 2 (quintet) 2.0 mp 1500 3 (doublet) 1.5 1000 3 (triplet) 1.0 C-81 Br 0.5 C-7⁹Br 500 0.0
% transmittance alkyl halide 4000 5.0 4.5 3500 1 (sextet) 4.0 CH (sp³) 3000 3.5 Molecule 5 2500 3.0 2000 wavenumber (cm-¹) 2.5 8 (ppm) 2 (quintet) 2.0 mp 1500 3 (doublet) 1.5 1000 3 (triplet) 1.0 C-81 Br 0.5 C-7⁹Br 500 0.0
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please what molecule is this

Transcribed Image Text:The image consists of two graphs which provide spectroscopic data for "Molecule 5."
### Top Graph: Infrared (IR) Spectrum
- **Y-axis:** % Transmittance
- **X-axis:** Wavenumber (cm⁻¹), ranging from 4000 to 500
#### Key Features:
- **Alkyl Halide Absorption:** Noted around the 3000 cm⁻¹ mark, indicating the presence of C-H (sp³) bonds.
- **Significant Peaks:** Two peaks are labeled as C-81Br and C-79Br, appearing close to 500 cm⁻¹, indicative of C-Br bond stretching.
### Bottom Graph: Nuclear Magnetic Resonance (NMR) Spectrum
- **Y-axis:** No specific label, generally represents intensity.
- **X-axis:** Chemical shift (δ, ppm), ranging from 5.0 to 0.0
#### Peak Characteristics:
1. **1 (sextet):** Appears around 3.8 ppm, likely representing a split peak due to coupling with adjacent protons.
2. **2 (quintet):** At approximately 1.7 ppm, showing a quintet pattern.
3. **3 (doublet and triplet):**
- *Doublet:* Around 1.4 ppm, typically suggesting two neighboring equivalent hydrogens.
- *Triplet:* Near 1.0 ppm, indicating three neighboring equivalent hydrogens.
These spectra are typically used to identify functional groups and structural components within the molecule, aiding in molecular characterization and analysis.
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The question is based on the concept of organic spectroscopy. We need to analyse the spectral data and identify the compound.
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