The angular position of a point on a rotating wheel is given by e = 4.65 + 4.52t2 + 3.90t°, where e is in radians and t is in seconds. At t = 0, what are (a) the point's angular position and (b) its angular velocity? (c) What is its angular velocity at t = 4.30 s? (d) Calculate its angular acceleration at t= 2.65 s. (e) Is its angular acceleration constant?

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Chapter1: Units, Trigonometry. And Vectors
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The angular position of a point on a rotating wheel is given by e = 4.65+ 4.52t2 + 3.90t, where e is in radians and tis in seconds. Att =
0, what are (a) the point's angular position and (b) its angular velocity? (c) What is its angular velocity at t = 4.30 s? (d) Calculate its
angular acceleration at t = 2.65 s. (e) Is its angular acceleration constant?
(a) Number i
Units
(b) Number
Units
(c) Number
i
Units
(d) Number
Units
(e) Number
>
Transcribed Image Text:The angular position of a point on a rotating wheel is given by e = 4.65+ 4.52t2 + 3.90t, where e is in radians and tis in seconds. Att = 0, what are (a) the point's angular position and (b) its angular velocity? (c) What is its angular velocity at t = 4.30 s? (d) Calculate its angular acceleration at t = 2.65 s. (e) Is its angular acceleration constant? (a) Number i Units (b) Number Units (c) Number i Units (d) Number Units (e) Number >
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