The analysis of the voltage, V for the cireuit given in Figure Q4 can be expressed in the following three equations: R;(i, – iz) + R2(i,- iz) = V,la Rziz + R4(i, – iz) + R¿(i, – i,) = V,la Rşiz + R4(i3 – i2) + R2(iz – i,) = V3la where R is the resistance and i is the current. Analyze the system of linear equations above for i1, iz, and iz by using Gauss elimination method with pivoting.

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Q4 The analysis of the voltage, V for the circuit given in Figure Q4 can be expressed in the
following three equations:
R1(i, – i2) + R2(i, – iz) = V,la
Rzi, + R4(i, – i;) + R; (i, – i,) = V2la
Rziz + R4(i3 - i2) + R2(i3 – i,) = V3la
where R is the resistance and i is the current. Analyze the system of linear equations above
for i1, i2, and iz by using Gauss elimination method with pivoting.
V1
OV
+ i
R2
100
R1
200
+
Va
2001aV
V2
ov
R4
100
R3
300
R3
250
Figure Q4
G.
Transcribed Image Text:Q4 The analysis of the voltage, V for the circuit given in Figure Q4 can be expressed in the following three equations: R1(i, – i2) + R2(i, – iz) = V,la Rzi, + R4(i, – i;) + R; (i, – i,) = V2la Rziz + R4(i3 - i2) + R2(i3 – i,) = V3la where R is the resistance and i is the current. Analyze the system of linear equations above for i1, i2, and iz by using Gauss elimination method with pivoting. V1 OV + i R2 100 R1 200 + Va 2001aV V2 ov R4 100 R3 300 R3 250 Figure Q4 G.
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