The amplitude of a scattered wave is given by S(0) = :(21 + 1)exp[idi ] sin 3, P(cos 0), where 0 is the angle of scattering, I is the angular momentum, Tk is the incident momentum, and & is the phase shift produced by the central potential that is doing the scattering. The total cross section is otot = S IS (0)*dQ. Show that 47 E(21 + 1) sin² & . Otot =

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The amplitude of a scattered wave is given by
1
S(0) =
(21 + 1)exp[id] sin 3i P(cos 0),
l=0
where e is the angle of scattering, I is the angular momentum, ik is
the incident momentum, and & is the phase shift produced by the
central potential that is doing the scattering. The total cross section
is oiot = S IS(O)²a2. Show that
47
Otot =
FL(21+ 1)sin² § .
%3D0
Transcribed Image Text:The amplitude of a scattered wave is given by 1 S(0) = (21 + 1)exp[id] sin 3i P(cos 0), l=0 where e is the angle of scattering, I is the angular momentum, ik is the incident momentum, and & is the phase shift produced by the central potential that is doing the scattering. The total cross section is oiot = S IS(O)²a2. Show that 47 Otot = FL(21+ 1)sin² § . %3D0
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