Answered: The amplitude of a scattered wave is… | bartleby

Related questions

Question

The amplitude of a scattered wave is given by
1
S(0) =
(21 + 1)exp[id] sin 3i P(cos 0),
l=0
where e is the angle of scattering, I is the angular momentum, ik is
the incident momentum, and & is the phase shift produced by the
central potential that is doing the scattering. The total cross section
is oiot = S IS(O)²a2. Show that
47
Otot =
FL(21+ 1)sin² § .
%3D0

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

Q.18. Verify the statement in the text that, if the phase velocity is the same for all wavelengths of a certain wave phenomenon (that is, there is no dispersion), the group and phase velocities are the same?
sin kx 2) Consider the wavefunction is given y(x) =2N For what value of N х will it be normalized? Hint: a useful integral is (sin dt 3) Prove that
During World War II, Sir Geoffrey Taylor, a British fl uiddynamicist, used dimensional analysis to estimate the wavespeed of an atomic bomb explosion. He assumed that theblast wave radius R was a function of energy released E , airdensity ρ , and time t . Use dimensional reasoning to showhow wave radius must vary with time.
Legrende polynomials The amplitude of a stray wave is defined by: SO) =x (21+ 1) exp li8,] sen 8, P(cos 8). INO Here e is the scattering angle, / is the angular momentum and 6, is the phase shift produced by the central potential that performs the scattering. The total cross section is: Show that: 'É4+ 1)sen² 8, .