- M₁M₂w¹ – 2C(M₁ + M₂)² + 2C²(1 — cos Ka) = 0. (22) We can solve this equation exactly for w², but it is simpler to examine the limiting cases Ka < 1 and Ka = ±π at the zone boundary. For small Ka we have cos Ka 1-K²a² + ..., and the two roots are 1 w² = 2C - ( 1₁ + M₂) C -K²a² M₁ + M₂ (optical branch); (acoustical branch). (23) (24)
- M₁M₂w¹ – 2C(M₁ + M₂)² + 2C²(1 — cos Ka) = 0. (22) We can solve this equation exactly for w², but it is simpler to examine the limiting cases Ka < 1 and Ka = ±π at the zone boundary. For small Ka we have cos Ka 1-K²a² + ..., and the two roots are 1 w² = 2C - ( 1₁ + M₂) C -K²a² M₁ + M₂ (optical branch); (acoustical branch). (23) (24)
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Given the (22) equation, prove that (23) and (24) are the frequencies of the optical and acoustic branch
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