The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.964 g and a standard deviation of 0.317 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 32 cigarettes with a mean nicotine amount of 0.914 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 32 cigarettes with a mean of 0.914 g or less. P(M< 0.914 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Assume that any probability below 5% is sufficient to conclude that the new product really have lower nicotine. Based on the result above, is it valid to claim that the amount of nicotine is lower? O Yes. The probability of this data is unlikely to have occurred by chance alone. O No. The probability of obtaining this data is high enough to have been a chance occurrence.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.964 g and a
standard deviation of 0.317 g. The company that produces these cigarettes claims that it has now reduced the
amount of nicotine. The supporting evidence consists of a sample of 32 cigarettes with a mean nicotine
amount of 0.914 g.
Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly
seleting 32 cigarettes with a mean of 0.914 g or less.
P(M< 0.914 g) =
Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or
z-scores rounded to 3 decimal places are accepted.
Assume that any probability below 5% is sufficient to conclude that the new product really have lower
nicotine. Based on the result above, is it valid to claim that the amount of nicotine is lower?
OYes. The probability of this data is unlikely to have occurred by chance alone.
O No. The probability of obtaining this data is high enough to have been a chance occurrence.
> Next Question
Transcribed Image Text:The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.964 g and a standard deviation of 0.317 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 32 cigarettes with a mean nicotine amount of 0.914 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 32 cigarettes with a mean of 0.914 g or less. P(M< 0.914 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Assume that any probability below 5% is sufficient to conclude that the new product really have lower nicotine. Based on the result above, is it valid to claim that the amount of nicotine is lower? OYes. The probability of this data is unlikely to have occurred by chance alone. O No. The probability of obtaining this data is high enough to have been a chance occurrence. > Next Question
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