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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 132 millimeters, and a variance of 64. If a random sample of 39 steel bolts is selected, what is the probability that the sample mean would be greater than 128.2 millimeters? Round your answer to four decimal places. Answer

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 132 millimeters, and a variance of 64. If a random sample of 39 steel bolts is selected, what is the probability that the sample mean would be greater than 128.2 millimeters? Round your answer to four decimal places. Answer

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 132 millimeters, and a variance of 64. If a random sample of 39 steel bolts is selected, what is the probability that the sample mean would be greater than 128.2 millimeters? Round your answer to four decimal places. **Answer** [How to enter your answer (opens in new window)](Link to answer entry guide) There are no graphs or diagrams associated with this text.
Transcribed Image Text:Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 132 millimeters, and a variance of 64. If a random sample of 39 steel bolts is selected, what is the probability that the sample mean would be greater than 128.2 millimeters? Round your answer to four decimal places. **Answer** [How to enter your answer (opens in new window)](Link to answer entry guide) There are no graphs or diagrams associated with this text.
**Standard Normal Distribution Table Explanation** This table represents the area to the left of a given Z score in the standard normal distribution. Each cell in the table shows the probability that a standard normal random variable will be less than or equal to the Z score. ### Structure of the Table: - **Rows and Columns**: - The first column lists Z scores from -3.9 to 0.0 in increments of 0.1. - The first row after the header indicates fractional increments of Z scores from .00 to .09. - **Finding Probabilities**: - To find the probability for a specific Z score, combine the row value with the column value. For example, to find the probability for Z = -1.38, locate the row for -1.3 and move to the column under .08. The value in this cell is 0.0838. This means there is an 8.38% probability that a standard normal random variable is less than -1.38. ### Notable Features: - **Highlighted Values**: - The table emphasizes Z scores of -1.3 and corresponding areas, which are important benchmarks in certain statistical analyses. - Highlighted by yellow boxes, the values at Z = -1.38 show a probability of 0.0838. ### Graphical Explanation: There are no graphs or diagrams included in this table. This table is purely numerical and used for statistical calculations involving the standard normal distribution. ### Usage: This table is essential for statistical analyses, allowing researchers and students to quickly find probabilities associated with specific standard normal variables. It is widely used in fields such as psychology, economics, engineering, and any science involving statistical methodologies.
Transcribed Image Text:**Standard Normal Distribution Table Explanation** This table represents the area to the left of a given Z score in the standard normal distribution. Each cell in the table shows the probability that a standard normal random variable will be less than or equal to the Z score. ### Structure of the Table: - **Rows and Columns**: - The first column lists Z scores from -3.9 to 0.0 in increments of 0.1. - The first row after the header indicates fractional increments of Z scores from .00 to .09. - **Finding Probabilities**: - To find the probability for a specific Z score, combine the row value with the column value. For example, to find the probability for Z = -1.38, locate the row for -1.3 and move to the column under .08. The value in this cell is 0.0838. This means there is an 8.38% probability that a standard normal random variable is less than -1.38. ### Notable Features: - **Highlighted Values**: - The table emphasizes Z scores of -1.3 and corresponding areas, which are important benchmarks in certain statistical analyses. - Highlighted by yellow boxes, the values at Z = -1.38 show a probability of 0.0838. ### Graphical Explanation: There are no graphs or diagrams included in this table. This table is purely numerical and used for statistical calculations involving the standard normal distribution. ### Usage: This table is essential for statistical analyses, allowing researchers and students to quickly find probabilities associated with specific standard normal variables. It is widely used in fields such as psychology, economics, engineering, and any science involving statistical methodologies.
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