The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.954 g and a standard deviation of 0.301 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 40 cigarettes with a mean nicotine amount of 0.902 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly selecting 40 cigarettes with a mean of 0.902 g or less. P(M < 0.902 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, zis it valid to claim that the amount of nicotine is lower? (Let's use a 5% cut-off for our definition of unusual.) O No. The probability of obtaining this data is high enough to have been a chance occurrence. O Yes. The probability of this data is unlikely to have occurred by chance alone.

MATLAB: An Introduction with Applications
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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.954 g and
a standard deviation of 0.301 g. The company that produces these cigarettes claims that it has now
reduced the amount of nicotine. The supporting evidence consists of a sample of 40 cigarettes with a mean
nicotine amount of 0.902 g.
Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly
selecting 40 cigarettes with a mean of 0.902 g or less.
P(M < 0.902 g)
Enter your answer as a number accurate to 4 decimal places.
NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Based on the result above, ¿is it valid to claim that the amount of nicotine is lower? (Let's use a 5% cut-off
for our definition of unusual.)
O No. The probability of obtaining this data is high enough to have been a chance occurrence.
O Yes. The probability of this data is unlikely to have occurred by chance alone.
Transcribed Image Text:The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.954 g and a standard deviation of 0.301 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 40 cigarettes with a mean nicotine amount of 0.902 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly selecting 40 cigarettes with a mean of 0.902 g or less. P(M < 0.902 g) Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, ¿is it valid to claim that the amount of nicotine is lower? (Let's use a 5% cut-off for our definition of unusual.) O No. The probability of obtaining this data is high enough to have been a chance occurrence. O Yes. The probability of this data is unlikely to have occurred by chance alone.
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