X Incorrect.The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes andstandard deviation 1.7 minutes. Suppose that a random sample of n = 47 customers is observed. Find the probability that theaverage time waiting in line for these customers is(a) Less than 10 minutes(b) Between 5 and 10 minutes(c) Less than 6 minutesRound your answers to four decimal places (e.g. 0.9876).(a) The probability is i 7.26(b) The probability is i -12.9(c) The probability is i -8.38

Answered: Image /qna-images/answer/66fad4e2-cb7a-4522-9f93-c2a29df04324.jpg

Answered: The amount of time that a customer…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 131000 dollars. Assume the standard deviation is 30000 dollars. Suppose you take a simple random sample of 83 graduates.Find the probability that a single randomly selected salary is at least 129000 dollars.P(X > 129000) = Find the probability that a sample of size n=83n=83 is randomly selected with a mean that is at least 129000 dollars.P(M > 129000) = Enter your answers as numbers accurate to 4 decimal place
Assume that your aunt wrote 139 letters to her family members in 2019. Let the random variable x represent the number of these letters that she wrote on a given day. Assume also that this scenario has a Poisson distribution. What is the mean number of letters written per day? Round to 3 decimal places. What is the standard deviation? Round to 3 decimal places.
A random variable X forms a normally distributed data set with mean 94.2 and standard deviation 2.41 . Determine the probability that X is at most 94.2. (Express your final answer in 4 decimal places)
The average amount of money spent for lunch per person in the college cafeteria is $6.24 and the standard deviation is $2.05. Suppose that 6 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible.For the group of 6 patrons, find the probability that the average lunch cost is between $6.2647 and $7.3532.
An electrical company claims that the average life of the bulbs it manufactures is 1200 hrs. with the standard deviation of 250 hrs. If a random sample of 100 bulbs is chosen, what is the probability that the sample mean will be. Greater than 1150 hrs. Less than 1250 hrs. Between 1150 and 1250 hrs.
A normal random variable x has an unknown mean and standard deviation. The probability that x exceeds 4 is 0.9772, and the probability that x exceeds 5 is 0.9332. Find mean and standard deviation. (show your calculation
Suppose a batch of steel rods produced at a steel plant have a mean length of 178 millimeters, and a standard deviation of 12 millimeters. If 76 rods are sampled at random from the batch, what is the probability that the mean length of the sample rods would differ from the population mean by less than 0.56 millimeters? Round your answer to four decimal places.
The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 68 minutes and a standard deviation of 16 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs . Round all answers to 4 decimal places where possible. b. Find the probability that a randomly selected person at the hot springs stays longer then 85 minutes. c. The park service is considering offering a discount for the 6% of their patrons who spend the least time at the hot springs. What is the longest amount of time a patron can spend at the hot springs and still receive the discount? ? minutes. d. Find the Inter Quartile Range (IQR) for time spent at the hot springs.Q1: ? minutes Q3: ? minutes IQR: ? minutes
The mean weight of all Goliath grouper caught on the Treasure coast is 367 pounds, with a standard deviation of 33 pounds. Suppose a random sample of 32 Goliath Grouper from the Treasure Coast are caught and weighed. Determine the probability that the average weight of the sample of 32 Goliath Grouper is within 7 pounds of the average weight of all Goliath Grouper caught on the Treasure Coast. Round the solution to four decimal places , if necessary .
Suppose that the distribution for total amounts spent by students vacationing for a week in Florida is normally distributed with a mean of 650 and a standard deviation of 120. Suppose you take a simple random sample (SRS) of 25 students from this distribution. ves. What is the probability that a SRS of 25 students will spend an average of between 600 and 700 dollars? Round to five decimal places.
The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 67 minutes and a standard deviation of 16 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs . Round all answers to 4 decimal places where possible.b. Find the probability that a randomly selected person at the hot springs stays longer then 77 minutes. c. The park service is considering offering a discount for the 4% of their patrons who spend the least time at the hot springs. What is the longest amount of time a patron can spend at the hot springs and still receive the discount? minutes.d. Find the Inter Quartile Range (IQR) for time spent at the hot springs.Q1: (. ) minutesQ3: ( )minutesIQR:( )minutes PLEASE ANSWER ALL 3 SUBS B, C, AND D
A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 18.5 weeks. Assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 9 weeks. Suppose you would like to select a random sample of 50 unemployed individuals for a follow-up study.Find the probability that a single randomly selected value is between 14.8 and 16.2.P(14.8 < X < 16.2) = Find the probability that a sample of size N =50 is randomly selected with a mean between 14.8 and 16.2.P(14.8 < M < 16.2) = Enter your answers as numbers accurate to 4 decimal places.

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