The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes andstandard deviation 1.7 minutes. Suppose that a random sample of n = 47 customers is observed. Find the probability that theaverage time waiting in line for these customers is(a) Less than 10 minutes(b) Between 5 and 10 minutes(c) Less than 6 minutesRound your answers to four decimal places (e.g. 0.9876).(a) The probability is i 0.29015(b) The probability is i(c) The probability is 00.29015Statistical Tables and Charts

Given,mean(μ)=8.2standard deviation(σ)=1.7sample size(n)=47

Answered: The amount of time that a customer…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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If the average length of all low-weight babies at the time of birth is known to be 36.5 centimeters with a standard deviation of 2.4 cm, use pnorm() to find the probability that the sample mean length is equivalent to the sample mean of our random sample or larger. random sample mean= 36.82
Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 149000 dollars. Assume the standard deviation is 44000 dollars. Suppose you take a simple random sample of 63 graduates.Find the probability that a single randomly selected salary is at least 144000 dollars.P(X > 144000) = 0.5438 wrong toFind the probability that a sample of size n=63n=63 is randomly selected with a mean that is at least 144000 dollars.P(M > 144000) = 0.8159 it is wrong is> no >or equal please
Service time for a customer coming through a checkout counter in a retail store is a random variable with the mean of 4.0 minutes and standard deviation of 2.0 minutes. Suppose that the distribution of service time is fairly close to a normal distribution. Suppose there are two counters in a store, n₁ = 46 customers in the first line and n₂ = 52 customers in the second line. Find the probability that the difference between the mean service time for the shorter line X₁ and the mean service time for the longer one X₂ is more than 0.3 minutes. Assume that the service times for each customer can be regarded as independent random variables. Round your answer to two decimal places (e.g. 98.76). P = !
The time taken in the cycling phase of a triathlon has a mean 23.16min and standard deviation 8.39min. Find the probability that the mean cycling time taken by a random sample of 38 competitors is greater than 25 minutes. Give your answer in 3 decimal places.
A dean in the business school claims that GMAT scores of applicants to the school's MBA program have increased during the past 5 years. Five years ago, the mean and standard deviation of GMAT scores of MBA applicants were 550 and 60, respectively. 30 applications for this year's program were randomly selected and the GMAT scores recorded. If we assume that the distribution of GMAT scores of this year's applicants is the same as that of 5 years ago, find the probability of erroneously concluding that there is not enough evidence to supports the claim when, in fact, the true mean GMAT score is 590. Assume αα is 0.02.
The high temperature xx (in degrees Fahrenheit) on January days in Columbus, Ohio, varies according to the Normal distribution with mean 20 and standard deviation 7. What is the probability that the temperature on a random January day in Columbus is below 10 degrees?
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Suppose the mean income of firms in the industry for a year is 2525 million dollars with a standard deviation of 77 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn less than 4040 million dollars? Round your answer to four decimal places.
A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 19.8 weeks. Assume that for the population of all unemployed individuals the population mean length of unemployment is 19.8 weeks and that the population standard deviation is 5.9 weeks. Suppose you would like to select a random sample of 152 unemployed individuals for a follow-up study. Find the probability that a single randomly selected value is between 19 and 20.7. P(19 < x < 20.7) = 0.1153 or Find the probability that a sample of size n = 152 is randomly selected with a mean between 19 and 20.7. P(19 << 20.7) = 0.9244 X Enter your answers as numbers accurate to 4 decimal places.
A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 18.5 weeks. Assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 9 weeks. Suppose you would like to select a random sample of 50 unemployed individuals for a follow-up study.Find the probability that a single randomly selected value is between 14.8 and 16.2.P(14.8 < X < 16.2) = Find the probability that a sample of size N =50 is randomly selected with a mean between 14.8 and 16.2.P(14.8 < M < 16.2) = Enter your answers as numbers accurate to 4 decimal places.

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