The amount of time that a clock works without adjusting is a random variable with exponential distribution with λ = 0.04 per day, calculate the probabilities that the clock must adjust in less than 30 days Show all the steps to arrive at the result of 0.6988, do not skip any steps to arrive at the result
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The amount of time that a clock works without adjusting is a random variable with exponential distribution with λ = 0.04 per day, calculate the probabilities that the clock must adjust in less than 30 days
Show all the steps to arrive at the result of 0.6988, do not skip any steps to arrive at the result
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- Two Independent random samples of n observations are to be selected from each of two binomial populations. If you wish to estimate the difference in the two population proportions correct to within 0.05, with probability equal to 0.98, how large should n be?X ~ Exp (1/9.848) 1) Find the expected value 2) Find the standard deviationREM (rapid eye movement) sleep is sleep during which most dreams occur. Each night a person has both REM and non-REM sleep. However, it is thought that children have more REM sleep than adults†. Assume that REM sleep time is normally distributed for both children and adults. A random sample of n1 = 9 children (9 years old) showed that they had an average REM sleep time of x1 = 2.9 hours per night. From previous studies, it is known that σ1 = 0.5 hour. Another random sample of n2 = 9 adults showed that they had an average REM sleep time of x2 = 2.20 hours per night. Previous studies show that σ2 = 0.7 hour. (a) What is the value of the sample test statistic? Compute the corresponding z or t value as appropriate. (Test the difference μ1 − μ2. Round your answer to two decimal places.)(b) Find (or estimate) the P-value. (Round your answer to four decimal places.) (c) Find a 98% confidence interval for μ1 − μ2. (Round your answers to two decimal places.) lower limit upper limit
- SAT scores in one state is normally distributed with a mean of 1532 and a standard deviation of 200. Suppose we randomly pick 50 SAT scores from that state. a) Find the probability that one of the scores in the sample is less than 1492. P(X < 1492) = b) Find the probability that the average of the scores for the sample of 50 scores is less than 1492. P(X < 1492) = Round each answer to at least 4 decimal places.REM (rapid eye movement) sleep is sleep during which most dreams occur. Each night a person has both REM and non-REM sleep. However, it is thought that children have more REM sleep than adults†. Assume that REM sleep time is normally distributed for both children and adults. A random sample of n1 = 11 children (9 years old) showed that they had an average REM sleep time of x1 = 2.5 hours per night. From previous studies, it is known that σ1 = 0.7 hour. Another random sample of n2 = 11 adults showed that they had an average REM sleep time of x2 = 2.00 hours per night. Previous studies show that σ2 = 0.6 hour. Do these data indicate that, on average, children tend to have more REM sleep than adults? Use a 10% level of significance. Solve the problem using both the traditional method and the P-value method. (Test the difference μ1 − μ2. Round the test statistic and critical value to two decimal places. Round the P-value to four decimal places.) test statistic critical value…REM (rapid eye movement) sleep is sleep during which most dreams occur. Each night a person has both REM and non-REM sleep. However, it is thought that children have more REM sleep than adults†. Assume that REM sleep time is normally distributed for both children and adults. A random sample of n1 = 9 children (9 years old) showed that they had an average REM sleep time of x1 = 2.9 hours per night. From previous studies, it is known that σ1 = 0.6 hour. Another random sample of n2 = 9 adults showed that they had an average REM sleep time of x2 = 2.10 hours per night. Previous studies show that σ2 = 0.8 hour. Do these data indicate that, on average, children tend to have more REM sleep than adults? Use a 1% level of significance. (a) What is the level of significance? What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to two decimal places.)(c) Find (or estimate) the P-value. (Round your answer to four decimal places.)
- Please show every step to solve the problem.The mean incubation time of fertilized chicken eggs kept at 100.5 degrees F in a still-air incubator is 21 days. Suppose that the incubation times are approximately normally distributed with a standard deviation of 1 day. Find an interpret the probability that a a sample of 12 selected fertilized chicken egg hatches in less than 20 days. Edit View Insert Format Tools Table BI U 2. 12pt v Paragraph v B Icauliflower seeds germinate in 6 days or more. Find the standard deviation of times taken for germination for cauliflower seeds. Carry your intermediate computations to at least four decimal places. Round your answer to at least two decimal places. Suppose that the times taken for germination for cauliflower seeds are normally distributed with a mean of 7 days. Suppose also that exactly 80% of the O days
- Customers arrive on average every 30 minutes to The Grease Monkey, an auto repair shop with only one mechanic. The inter-arrival times are exponentially distributed. Repair times are variable with a mean of 25 minutes and a standard deviation of 20 minutes. The mechanic works on one vehicle at a time from beginning to end and takes in any waiting vehicles on a first-come first-served basis. The garage itself has room for only one vehicle at a time, so waiting vehicles are kept in the parking lot where there are always plenty of spaces available. Assume customers never balk or renege. a)What is the average number of cars in the garage (not including the parking lot)? b) How long (in minutes) do vehicles wait on average in the adjacent parking lot? c) The competitor shop across the street also has a single mechanic and an average of 3.1 vehicles waiting in its parking lot. The competitor only does oil changes, which take an average of 21 minutes. Customer inter-arrival times to the…REM (rapid eye movement) sleep is sleep during which most dreams occur. Each night a person has both REM and non-REM sleep. However, it is thought that children have more REM sleep than adults†. Assume that REM sleep time is normally distributed for both children and adults. A random sample of n1 = 8 children (9 years old) showed that they had an average REM sleep time of x1 = 2.9 hours per night. From previous studies, it is known that ?1 = 0.9 hour. Another random sample of n2 = 8 adults showed that they had an average REM sleep time of x2 = 2.00 hours per night. Previous studies show that ?2 = 0.6 hour. Do these data indicate that, on average, children tend to have more REM sleep than adults? Use a 1% level of significance. (a) What is the level of significance?State the null and alternate hypotheses. H0: ?1 = ?2; H1: ?1 ≠ ?2H0: ?1 = ?2; H1: ?1 < ?2 H0: ?1 = ?2; H1: ?1 > ?2H0: ?1 < ?2; H1: ?1 = ?2 (b) What sampling distribution will you use? What assumptions are you…The occurrence of traffic accidents at an intersection may be modeled as a Poisson process. Based on historical records the average rate of accidents is once every 6 years. Part 1 What is the probability that there will be no accidents at the intersection for a period of 3 years? (Answer correct to 3 decimal places.) number (rtol=0.001, atol=D0.001) Part 2 Suppose that in every accident at the intersection, there is a 5% probability of fatality. Based on the above Poisson model what is the probability of one traffic fatality at this intersection in a period of 3 years? (Answer correct to 3 decimal places.) Hint: Note that here you need to find the mean rate of fatalities per year, first. number (rtol=0.001, atol=D0.001)
