The amount of ozone in a mixture of gases can be deter- mined by passing the mixture through an acidic aqueous solution of potassium iodide, where the ozone reacts according to O3 (g) + 3 I¯(aq)+ H2O(€) O2 (g) + I5 (aq) + 2 OH¯(aq) to form the triiodide ion Iz. The amount of triiodide pro- duced is then determined by titrating with thiosulfate solution: I5 (aq) + 2 S203 (aq) 31 (aq) + S,O (aq) A small amount of starch solution is added as an indicator because it forms a deep-blue complex with the triiodide solution. Disappearance of the blue color thus signals the completion of the titration. Suppose 53.2 L of a gas mixture at a temperature of 18°C and a total pressure of 0.993 atm is passed through a solution of potassium iodide until the ozone in the mixture has reacted completely. The solution requires 26.2 mL of a 0.1359-M solution of thiosulfate ion to titrate to the endpoint. Calculate the mole fraction of ozone in the original gas sample.
The amount of ozone in a mixture of gases can be deter- mined by passing the mixture through an acidic aqueous solution of potassium iodide, where the ozone reacts according to O3 (g) + 3 I¯(aq)+ H2O(€) O2 (g) + I5 (aq) + 2 OH¯(aq) to form the triiodide ion Iz. The amount of triiodide pro- duced is then determined by titrating with thiosulfate solution: I5 (aq) + 2 S203 (aq) 31 (aq) + S,O (aq) A small amount of starch solution is added as an indicator because it forms a deep-blue complex with the triiodide solution. Disappearance of the blue color thus signals the completion of the titration. Suppose 53.2 L of a gas mixture at a temperature of 18°C and a total pressure of 0.993 atm is passed through a solution of potassium iodide until the ozone in the mixture has reacted completely. The solution requires 26.2 mL of a 0.1359-M solution of thiosulfate ion to titrate to the endpoint. Calculate the mole fraction of ozone in the original gas sample.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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
Transcribed Image Text:The amount of ozone in a mixture of gases can be deter-
mined by passing the mixture through an acidic aqueous
solution of potassium iodide, where the ozone reacts
according to
O3 (g) + 3 I¯(aq)+ H2O(€)
O2 (g) + I5 (aq) + 2 OH¯(aq)
to form the triiodide ion Iz. The amount of triiodide pro-
duced is then determined by titrating with thiosulfate
solution:
I5 (aq) + 2 S203 (aq) 31 (aq) + S,O (aq)
A small amount of starch solution is added as an indicator
because it forms a deep-blue complex with the triiodide
solution. Disappearance of the blue color thus signals the
completion of the titration. Suppose 53.2 L of a gas mixture
at a temperature of 18°C and a total pressure of 0.993 atm
is passed through a solution of potassium iodide until the
ozone in the mixture has reacted completely. The solution
requires 26.2 mL of a 0.1359-M solution of thiosulfate ion
to titrate to the endpoint. Calculate the mole fraction of
ozone in the original gas sample.
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