Sodium hydrogen carbonate (NaHCO,), also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid (HCI) , which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO, neutralizes excess HCl through this reaction: HCl(aq) + NaHCO;(aq) → NaCl(aq) + H,O(1) + CO,(g) The CO, gas produced is what makes you burp after drinking the solution. Suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 50. mL of a 0.089 M HCI solution. What mass of NaHOCO, would he need to ingest to neutralize this much HCl ? Be sure your answer has the correct number of significant digits.

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### Understanding the Neutralization Reaction using Sodium Bicarbonate

Sodium hydrogen carbonate (NaHCO₃), also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid (HCl), which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO₃ neutralizes excess HCl through this reaction:

\[ \text{HCl(aq)} + \text{NaHCO}_3 \text{(aq)} \rightarrow \text{NaCl(aq)} + \text{H}_2\text{O(l)} + \text{CO}_2\text{(g)} \]

The CO₂ gas produced is what makes you burp after drinking the solution.

#### Example Calculation
Suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 50.0 mL of a 0.089 M HCl solution. What mass of NaHCO₃ would he need to ingest to neutralize this much HCl? Be sure your answer has the correct number of significant digits.

**Calculation Steps:**
1. **Determine the moles of HCl:**
   \[
   \text{Moles of HCl} = \text{Volume (L)} \times \text{Molarity (M)}
   \]
   \[
   50.0 \text{ mL} = 0.0500 \text{ L}
   \]
   \[
   \text{Moles of HCl} = 0.0500 \text{ L} \times 0.089 \text{ M} = 0.00445 \text{ moles HCl}
   \]

2. **Determine the moles of NaHCO₃ required:**
   The balanced equation shows a 1:1 molar ratio between HCl and NaHCO₃, so the moles of NaHCO₃ required will be the same as the moles of HCl.
   \[
   \text{Moles of NaHCO}_3 = 0.00445 \text{ moles}
   \]

3. **Convert moles of NaHCO₃ to grams:**
   \[
   \text{Mass (g
Transcribed Image Text:### Understanding the Neutralization Reaction using Sodium Bicarbonate Sodium hydrogen carbonate (NaHCO₃), also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Acid indigestion is the burning sensation you get in your stomach when it contains too much hydrochloric acid (HCl), which the stomach secretes to help digest food. Drinking a glass of water containing dissolved NaHCO₃ neutralizes excess HCl through this reaction: \[ \text{HCl(aq)} + \text{NaHCO}_3 \text{(aq)} \rightarrow \text{NaCl(aq)} + \text{H}_2\text{O(l)} + \text{CO}_2\text{(g)} \] The CO₂ gas produced is what makes you burp after drinking the solution. #### Example Calculation Suppose the fluid in the stomach of a man suffering from indigestion can be considered to be 50.0 mL of a 0.089 M HCl solution. What mass of NaHCO₃ would he need to ingest to neutralize this much HCl? Be sure your answer has the correct number of significant digits. **Calculation Steps:** 1. **Determine the moles of HCl:** \[ \text{Moles of HCl} = \text{Volume (L)} \times \text{Molarity (M)} \] \[ 50.0 \text{ mL} = 0.0500 \text{ L} \] \[ \text{Moles of HCl} = 0.0500 \text{ L} \times 0.089 \text{ M} = 0.00445 \text{ moles HCl} \] 2. **Determine the moles of NaHCO₃ required:** The balanced equation shows a 1:1 molar ratio between HCl and NaHCO₃, so the moles of NaHCO₃ required will be the same as the moles of HCl. \[ \text{Moles of NaHCO}_3 = 0.00445 \text{ moles} \] 3. **Convert moles of NaHCO₃ to grams:** \[ \text{Mass (g
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