The aluminum post shown in the below figure is reinforced with a brass core. The assembly supports an axial compressive load of P = 9.75 kip and this load is applied to the rigid cap,. Take Eal = 10 x 103 ksi and Ebr = 15 x 103 ksi. Now Consider the applied
Plane Trusses
It is defined as, two or more elements like beams or any two or more force members, which when assembled together, behaves like a complete structure or as a single structure. They generally consist of two force member which means any component structure where the force is applied only at two points. The point of contact of joints of truss are known as nodes. They are generally made up of triangular patterns. Nodes are the points where all the external forces and the reactionary forces due to them act and shows whether the force is tensile or compressive. There are various characteristics of trusses and are characterized as Simple truss, planar truss or the Space Frame truss.
Equilibrium Equations
If a body is said to be at rest or moving with a uniform velocity, the body is in equilibrium condition. This means that all the forces are balanced in the body. It can be understood with the help of Newton's first law of motion which states that the resultant force on a system is null, where the system remains to be at rest or moves at uniform motion. It is when the rate of the forward reaction is equal to the rate of the backward reaction.
Force Systems
When a body comes in interaction with other bodies, they exert various forces on each other. Any system is under the influence of some kind of force. For example, laptop kept on table exerts force on the table and table exerts equal force on it, hence the system is in balance or equilibrium. When two or more materials interact then more than one force act at a time, hence it is called as force systems.
The aluminum post shown in the below figure is reinforced with a brass core. The
assembly supports an axial compressive load of P = 9.75 kip and this load is applied to
the rigid cap,. Take Eal = 10 x 103 ksi and Ebr = 15 x 103 ksi. Now Consider the applied
compressive load P = 9.75 kip at the point A, considering the rigid cap if firmly welded
to the aluminum post. You also need to consider that there is no core brass material; now,
you have a hollow cylinder with a rigid cap.
I =?(??^4−?i^4)/(64); O means outer and I means inner diameter.
a. Draw the Free Body Diagram (F.B.D) , considering a section perpendicular to the
longitudinal axis. Please clearly show that section plane along with either upper of
the body.
b. Shall there be any shear and/or moment as an internal loading on the section,
which you already have drawn?
c. Determine the normal stress at the point M and at the point N.
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