The ages (in years) and heights (in inches) of all pitchers for a baseball team are listed. Find the coefficient of variation for each of the two data sets. Then compare the results. :: Click the icon to view the data sets. CV neights % (Round to one decimal place as needed.)

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The ages (in years) and heights (in inches) of all pitchers for a baseball team are listed. Find the coefficient of variation for each of the two data sets. Then compare the
results.
E Click the icon to view the data sets.
CV neights
= % (Round to one decimal place as needed.)
Data Table
Heights
Ages
78
23
78
26
74
23
78
24
75
25
78
27
77
31
75
28
79
26
78
36
74
36
78
37
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Transcribed Image Text:Homework: Section 2.4 Homework Save Score: 0 of 1 pt 10 of 10 (9 complete) v HW Score: 70%, 7 of 10 pts 2.4.47 Question Help The ages (in years) and heights (in inches) of all pitchers for a baseball team are listed. Find the coefficient of variation for each of the two data sets. Then compare the results. E Click the icon to view the data sets. CV neights = % (Round to one decimal place as needed.) Data Table Heights Ages 78 23 78 26 74 23 78 24 75 25 78 27 77 31 75 28 79 26 78 36 74 36 78 37 Enter your answer in the answer box and then click Che Print Done 2 parts remaining Clear All Check Answer 近
Expert Solution
Step 1

CV calculation for Height (inches)

The sample size is n=12n = 12. We need to compute the sample mean Xˉ\bar X and sample variance s2s^2 are shown in the table below:

  Height Height2
  78 6084
  78 6084
  74 5476
  78 6084
  75 5625
  78 6084
  77 5929
  75 5625
  79 6241
  78 6084
  74 5476
  78 6084
Sum = 922 70876

The sample mean Xˉ\bar X is computed as follows:

Xˉ=1ni=1nXi=92212=76.833 \bar X = \frac{1}{n} \sum_{i=1}^n X_i = \frac{ 922}{ 12} = 76.833

Also, the sample variance s2s^2 is

s2=1n1(i=1nXi21n(i=1nXi)2)=1121(70876922212)=3.242s^2 = \frac{ 1}{n-1}\left(\sum_{i=1}^n X_i^2 - \frac{1}{n}\left(\sum_{i=1}^n X_i\right)^2 \right) = \frac{ 1}{ 12-1}\left( 70876 - \frac{ 922^2}{ 12} \right) = 3.242

Therefore, the sample standard deviation ss is

s=s2=3.242=1.801s = \sqrt{s^2} = \sqrt{ 3.242} = 1.801

Now,

We all know that Coefficient of variation , CV is

Statistics homework question answer, step 1, image 1

CVheights = 1.80176.833×100 = 2.344%

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