The advertised claim for batteries for cell phones is set at 48 operating hours. The operatinghours of 5000 batteries is tested and 0.28% of them failed during the advertised period. Doesthis experimental result support the claim that less than 0.2 percent of the company's batterieswill fail during the advertised period? Use hypothesis testing procedure with α = 0.01. (Hint:The alternative hypothesis is what you might believe to be true or hope to prove true.)

Hypothesis Test for the ProportionIf the unknown proportion is not expected to be too close to 0 or…

Answered: The advertised claim for batteries for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65-74 years: n = 117, x = 12.2, and s = 6.60. Does this data indicate that average daily zinc intake in the population of all males age 65-74 falls below the recommended allowance? (Use a = 0.05.) State the appropriate null and alternative hypotheses. Ο H, μ 15 Ha: u > 15 Ho:H = 15 Ha: u < 15 Ο H: μ= 15 H: u + 15 Ο H: μ= 15 H3: Hs 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) P-value =
20% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 356 randomly selected students who receive financial aid, 61 of them volunteered their time. What can be concluded at the αα = 0.10 level of significance? For this study, we should use? Select an answer z-test for a population proportion? or t-test for a population mean? The null and alternative hypotheses would be: H0:H0:? μ or p Select an answer ≥ = < > ≤ ≠ _______(please enter a decimal) H1:H1:? μ or p Select an answer ≥ ≠ = < > ≤ _______ (Please enter a decimal) 2. The test statistic ? t or z = ______ (please show your answer to 3 decimal places.) The p-value = ______ (Please show your answer to 4 decimal places.) The p-value is ? > or ≤ α 3. Based on this, we should Select an answer fail to reject? reject ? accept ? the null…
The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65-74 years: n = 113, x = 12.4, and s = 6.63. Does this data indicate that average daily zinc intake in the population of all males age 65-74 falls below the recommended allowance? (Use a = 0.05.) State the appropriate null and alternative hypotheses. O Ho: H = 15 H: u > 15 O Ho: H = 15 H: u < 15 Ο H: μ15 H:us 15 Ο Η: μ- 15 H: u = 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = p-value = State the conclusion in the problem context. O Reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. O Do not reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. O Do not reject the null hypothesis. There…
Molly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She obtains a random sample of 120 containers of ground beef and finds that 84 percent have the correct fat content. Molly then conducts a hypothesis test of H0:p=0.80H0:p=0.80 versus Ha:p≠0.80Ha:p≠0.80 and calculates a test statistic of 1.10 with a pp-value of 0.273. Which of the following best represents the meaning of the pp-value? If the population proportion is 0.84, the probability of observing a sample proportion of 0.80 is 0.273. A If the population proportion is 0.84, the probability of observing a sample proportion of at least 0.04 less than 0.84 is 0.273. B If the population proportion is 0.80, the probability of observing a sample proportion within 0.04 of 0.80 is 0.273. C If the population proportion is 0.80, the probability of observing a sample proportion at least 0.04 greater than 0.80 is 0.273. D If the…
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The local Hannaford was tracking the proportion of customers who bought flour in their stores. In mid-March they found that 65% of customers were buying flour when it was available. They want to know if that percentage has decreased now that flour is more readily available. Their hypotheses are: Ho: ρ ≥ .65 and Ha: ρ < .65. They sample 200 customers and found that 120 of them bought flour. What is the computed test statistic? Calculate the z or t, whichever is appropriate, and give the result rounded to 2 decimal places. If it's a negative number, put the negative sign before the number with no spaces between it and the number.
14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer = ≠ > < (please enter a decimal) H1: ? p μ Select an answer < > = ≠ (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so…
Both, the Cohen's d and confidence interval, measure the impact of the IV on the DV. The only difference is that the confidence interval does so for the population, whereas the Cohen's d does so for the sample.
When using an independent samples t-test, the author of a journal article reported that t(30) = 3.60, p < .05. Should the researcher reject the null or fail to reject the null?
Generally speaking, would you say that most people can be trusted? A random sample of n1 = 257 people in Chicago ages 18-25 showed that r1 = 40 said yes. Another random sample of n2 = 281 people in Chicago ages 35-45 showed that r2 = 70 said yes. Does this indicate that the population proportion of trusting people in Chicago is higher for the older group? Use α = 0.01. (a) What is the level of significance? (b) What is the value of the sample test statistic? (Test the difference p1 − p2. Do not use rounded values. Round your final answer to two decimal places.)(c) Find (or estimate) the P-value. (Round your answer to four decimal places.)
Confidence in banks: A poll conducted in 2012 asked a random sample of 1217 adults in the United States how much confidence they had in banks and other financial institutions. A total of 160 adults said that they had a great deal of confidence. An economist claims that greater than 11% of U.S. adults have a great deal of confidence in banks. Can you conclude that the economist's claim is true? Use both =α0.05 and =α0.10 levels of significance and the P-value method with the TI-84 Plus calculator. (a) State the appropriate null and alternate hypotheses. :H0 :H1
please check this. The recidivism rate for convicted sex offenders is 14%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 324 convicted sex offenders who were also drug addicts, 32 of them became repeat offenders. What can be concluded at the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly different from 14% at αα = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders…

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