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The accompanying table lists the "attribute" ratings made by a random sample of participants in a speed dating session. Each attribute rating is the sum of the ratings of five attributes (sincerity, intelligence, fun, ambition, shared interests). Use a 0.05 significance level to test the claim that there is a difference between female attribute ratings and male attribute ratings. Click the icon to view the data on attribute ratings. In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the rating of the male minus the rating of the female. What are the null and alternative hypotheses for the hypothesis test? Ho Hd H₁ Hd (Type integers or decimals. Do not round.) Identify the test statistic. t = (Round to two decimal places as needed.) Identify the P-value. P-value (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is ratings. the significance level, the null hypothesis. There sufficient evidence to support the claim that there is a difference between female attribute ratings and male attribute Attribute Ratings Rating of Male by Female Rating of Female by Male 35 25 25 44 30 49 39 36 21 42

The accompanying table lists the "attribute" ratings made by a random sample of participants in a speed dating session. Each attribute rating is the sum of the ratings of five attributes (sincerity, intelligence, fun, ambition, shared interests). Use a 0.05 significance level to test the claim that there is a difference between female attribute ratings and male attribute ratings. Click the icon to view the data on attribute ratings. In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the rating of the male minus the rating of the female. What are the null and alternative hypotheses for the hypothesis test? Ho Hd H₁ Hd (Type integers or decimals. Do not round.) Identify the test statistic. t = (Round to two decimal places as needed.) Identify the P-value. P-value (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is ratings. the significance level, the null hypothesis. There sufficient evidence to support the claim that there is a difference between female attribute ratings and male attribute Attribute Ratings Rating of Male by Female Rating of Female by Male 35 25 25 44 30 49 39 36 21 42

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The accompanying table lists the "attribute" ratings made by a random sample of participants in a speed dating session. Each attribute rating is the sum of the ratings of five attributes (sincerity, intelligence, fun, ambition, shared interests). Use a 0.05 significance level to test the claim that there is a difference between female attribute ratings and male attribute ratings. Click the icon to view the data on attribute ratings. In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the rating of the male minus the rating of the female. What are the null and alternative hypotheses for the hypothesis test? Ho Hd H₁ Hd (Type integers or decimals. Do not round.) Identify the test statistic. t = (Round to two decimal places as needed.) Identify the P-value. P-value (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is ratings. the significance level, the null hypothesis. There sufficient evidence to support the claim that there is a difference between female attribute ratings and male attribute Attribute Ratings Rating of Male by Female Rating of Female by Male 35 25 25 44 30 49 39 36 21 42
Transcribed Image Text:The accompanying table lists the "attribute" ratings made by a random sample of participants in a speed dating session. Each attribute rating is the sum of the ratings of five attributes (sincerity, intelligence, fun, ambition, shared interests). Use a 0.05 significance level to test the claim that there is a difference between female attribute ratings and male attribute ratings. Click the icon to view the data on attribute ratings. In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the rating of the male minus the rating of the female. What are the null and alternative hypotheses for the hypothesis test? Ho Hd H₁ Hd (Type integers or decimals. Do not round.) Identify the test statistic. t = (Round to two decimal places as needed.) Identify the P-value. P-value (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is ratings. the significance level, the null hypothesis. There sufficient evidence to support the claim that there is a difference between female attribute ratings and male attribute Attribute Ratings Rating of Male by Female Rating of Female by Male 35 25 25 44 30 49 39 36 21 42
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