The accompanying table gives amounts of arsenic in samples of brown rice from three different states. The amounts are in micrograms of arsenic and all samples have the same serving size. The data are from the Food and Drug Administration. Use a 0.05 significance level totest the claim that the three samples are from populations with the same mean. Do the amounts of arsenic appear to be different in the different states? Given that the amounts of arsenic in the samples from Texas have the highest mean, can we conclude that brown rice fromTexas poses the greatest health problem?Click the icon to view the data.What are the hypotheses for this test?O A. Ho: At least one of the means is different from the othersH₁: H₁ H₂ =H3OB. Ho: H₁ H₂=H3H₁: At least one of the means is different from the othersOC. Ho: H₁ H₂ H3H₁: H₁ H₂ H3O D. Ho: H₁ H₂=H3H₁: H₁H₂ H3Arsenic AmountsArkansas | 4.82 4.94| 5.01 5.35 35 5.38|5.63|5.57 | 5.60 5.89 5.95 6.06California 1.47 3.69 3.97 4.45 4.92 5.10 5.32 5.39 5.35 5.45 5.55 5.61Texas5.55 5.75 6.55 6.90 6.86 6.93 7.10 7.30 7.47 7.59 7.74 7.68PrintDone(…)

The given data is Arkansas 4.82 4.94 5.01 5.35 5.35 5.38 5.63 5.57 5.6 5.89 5.95 6.06…

Answered: The accompanying table gives amounts of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You may need to use the appropriate appendix table or technology to answer this question. According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is $32.48. A New England-based lifestyle magazine wants to determine if red wines of the same quality are less expensive in Providence, and it has collected prices for 65 randomly selected red wines of similar quality from wine stores throughout Providence. The mean and standard deviation for this sample are $30.15 and $12, respectively. (a) Develop appropriate hypotheses for a test to determine whether the sample data support the conclusion that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48. (Enter != for ≠ as needed.) H0: Ha: (b) Using the sample from the 65 bottles, what is the test statistic? (Round your answer to three decimal…
You may need to use the appropriate appendix table or technology to answer this question. According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is $32.48. A New England-based lifestyle magazine wants to determine if red wines of the same quality are less expensive in Providence, and it has collected prices for 65 randomly selected red wines of similar quality from wine stores throughout Providence. The mean and standard deviation for this sample are $30.15 and $12, respectively. (d) Repeat the preceding hypothesis test using the critical value approach. State the null and alternative hypotheses. (Enter != for ≠ as needed.) H0: Ha: Find the value of the test statistic. (Round your answer to three decimal places.) State the critical values for the rejection rule. Use ? = 0.05. (Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused tail.)…
A contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 6060 people she sampled who work out in the morning have a mean of 3.33.3 hours of exercise each week. The 4747 people surveyed who exercise in the afternoon or evening have a mean of 3.43.4 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.40.4 hours for people who exercise in the morning and 0.70.7 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2 : Construct a 99%99% confidence interval for the true difference…
The state Government gives grants to low-income undergraduate students. According to the National Postsecondary Student Aid Study conducted by the U.S. Department of Education in 2008, the average Pell grant award for 2007-2008 was $2,600. We wonder if the mean amount is different this year for Pell grant recipients at San Jose State University. Suppose that we randomly select 50 Pell grant recipients from San Jose State University. For these 50 students, the mean Pell grant award is $2,450 with a standard deviation of $600. Let µ = the mean amount of Pell grant awards received by San Jose State University Pell grant recipients this year. We test the hypotheses: H0: μ = 2,600 , Ha: μ ≠ 2,600. The sample size is greater than 30, so a t-model is a good fit for the sampling distribution. What is the t-test statistic? What is the P-value?
In a city with three high schools, all the ninth graders took a Standardized Test, with these results: Mean High Number of ninth Test School graders (Frequency) Score Glenwood 83 263 Central 94 323 Lincoln 70 184 The city's PR manager, who never took statistics, claimed the mean score of all ninth graders in the city was the average of 83, 94, and 70, which is 82.3. Of course, that is incorrect. What is the mean score for all ninth graders in the city? Round to one decimal place. Mean of all ninth grader's scores =
Create and fill in a table with columns for (1) bin, (2) absolute frequency, and (3) relative frequency. Draw a histogram of the relative frequency distribution of Commuting Time in your sample. How would you characterize the shape of your histogram (e.g. uniform, symmetric, etc.)?
A marketing firm is doing research for an internet-based company. It wants to appeal to the age group of people who spend the most money online. The company wants to know if there is a difference in the mean amount of money people spend per morith on Internet purchases depending on their age bracket. The marketing firm looked at two age groups, 18-24 years and 25-30 years, and collected the data shown in the following table. Let Population 1 be the amount of money spent per month on internet purchases by people in the 18-24 age bracket and Population 2 be the amount of money spent per month on internet purchases by people in the 25-30 age bracket. Assume that the population variances are not the same. Internet Spending per Month 18-24 Years Answer Mean Amount Spent Standard Deviation Sample Size Step 1 of 2: Construct a 99 % confidence interval for the true difference between the mean amounts of money per month that people in these two age groups spend on Internet purchases. Round the…
Only letters C and D
You may need to use the appropriate technology to answer this question. Suppose the mean price for used cars is $10,198. A manager of a Kansas City used car dealership reviewed a sample of 50 recent used car sales at the dealership in an attempt to determine whether the population mean price for used cars at this particular dealership differed from the national mean. The prices for the sample of 50 cars are shown in the file named UsedCars. 12,400 10,400 12,100 10,000 11,000 8,895 7,675 9,975 6,350 10,470 9,895 11,250 8,795 12,500 9,340 10,150 9,200 9,395 11,000 10,640 10,000 7,500 8,000 10,440 10,200 10,300 9,740 9,280 10,930 8,000 9,000 7,680 9,400 10,730 7,350 12,240 11,970 8,240 9,910 10,080 9,440 8,970 9,500 10,050 10,130 11,400 8,500 7,500 9,090 10,500 (a) Formulate the hypotheses that can be used to determine whether a difference exists in the mean price for used cars at the dealership. H0: μ ≤ 10,198 Ha: μ > 10,198 H0: μ = 10,198 Ha: μ ≠ 10,198 H0: μ…
A randomly sampled group of patients at a major U.S. regional hospital became part of a nutrition study on dietary habits. Part of the study consisted of a 50-question survey asking about types of foods consumed. Each question was scored on a scale from one (most unhealthy behavior) to five (most healthy behavior). The answers were summed and averaged. The population of interest is the patients at the regional hospital. A prior survey of patients had found the mean score for the population of patients to be μ=2.9 After careful review of these data, the hospital nutritionist decided that patients could benefit from nutrition education. The current survey was implemented after patients were subjected to this education, and it produced the following sample statistics for the 15 patients sampled: x¯=3.5 and s=1.2 We would like to know if the education improved nutrition behavior. We test the hypotheses H0:μ=2.9 versus Ha:μ>2.9. The tt test to be used has the test statistic: Answer:
A contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 57 people she sampled who work out in the morning have a mean of 4.8 hours of exercise each week. The 56 people surveyed who exercise in the afternoon or evening have a mean of 4.2 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.8 hours for people who exercise in the morning and 0.3 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2 : Construct a 95% confidence interval for the true difference between the mean amounts…
Please answers questions a through d. Thank you!

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