The accepted resistivity value at room temperature for copper wire is 1.7421 x 10-8 ohm meter. please explain why or why not the measurements recorded are within some percent error of thius value. calculate resistivity and show the percent error. Use R=p L/A Using the formula calculate p L (m) Description Diameter (m) Resistance (ohm)0.10.002460.10.002510.10.002500.20.002520.20.002570.40.002550.40.002230.20.002520.20.002520.20.00274(straight)(bent)(annealed)0.0004080.0003610.0003710.0007750.0006670.0001430.0001570.0008220.0008480.000732

Answered: The accepted resistivity value at room…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The accepted resistivity value at room temperature for copper wire is 1.7421 x 10^-8ohm meter. please explain why or why not the measurements recorded are within some percent error of thius value. calculate resistivity and show the percent error. Use R=p L/A

Using the formula calculate p

L (m) Description Diameter (m) Resistance (ohm)
0.1
0.00246
0.1
0.00251
0.1
0.00250
0.2
0.00252
0.2
0.00257
0.4
0.00255
0.4
0.00223
0.2
0.00252
0.2
0.00252
0.2
0.00274
(straight)
(bent)
(annealed)
0.000408
0.000361
0.000371
0.000775
0.000667
0.000143
0.000157
0.000822
0.000848
0.000732

Expert Solution

Step 1

To find:

The resistivity and the percentage error.

Given:

The resistivity at room temperature for copper wire is $ρ = 1.7421 \times 10^{- 8} Ωm$ .

Formula used:

The expression for the resistance of the wire is,

$R = \frac{ρ L}{A}$

Here, $A$ is area, $L$ is length of wire and $ρ$ is resistivity.

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