The acceleration of a particle is defined by the a = -10v knowing that at tso the velocity is 30 m/sec find @ the distance that the particle will travel before Coming be rest - time required for the partick to come to rest. the time required for the velocity to be reduced 1%, of its initial value.

The acceleration of a particle is defined by the a = -10v knowing that at tso the velocity is 30 m/sec find @ the distance that the particle will travel before Coming be rest - time required for the partick to come to rest. the time required for the velocity to be reduced 1%, of its initial value.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Applying principles of dynamics (with step by steep solutions pls i give 5 stars) The displacement of a particle which moves along the x axis is given by x = (-4 + 3t2)e-0.25t, consider x to be in feet and t in seconds. Plot the displacement, velocity and acceleration for the first 20 seconds of motion and determine, both graphically and by your established equation for acceleration,the time at which acceleration is 0. (If the students find it more comfortable, they may choose to graph using excel or any graphing software, solutions however must be done manually)
A particle moving along a straight line has an acceleration which varies according to position as shown. If the velocity of the particle at the position x -6 ft is v = 5 ft/sec, determine the velocity v when x 13 ft. a, ft/sec2 7. -6 11 13 x, ft Part 1 13ft Calculate a dx. -6ft a, ft/seç? 7 -6 11 13 x, ft 131 Answer: a dx = ft2/sec? -6ft eTextbook and Media Save for Later Attempts: 0 of 2 used Submit Answer Using multiple attempts will impact your score す

A particle is moving along a straight road with its acceleration given by a = (2t – 1) m/s? for the five seconds and then continues with a constant velocity. At t = 0 seconds, the velocity of the particle is - 6 m/s and the particle displacement is 10 m. Draw (a – t) and (v – t) graphs for the time interval 0
A curvilinear motion of a particle is defined by V,=40-15t and y=75-312, where V, is in meters per second, y is in meters and t is in seconds. It is also known that x-D0 when t=0. Which of the following gives the nearest value of the acceleration when x=0 at the second value of time? Select the correct response: O 17.274 m/s2 O26.155 m/s2 16.155 m/s2 15.655 m/s?
• 1. A particle position given by s(t) = 4 t2 - 32 t +36 with s in meters and t in seconds. At what position does the particle come to a # 1 %3D momentary stop to reverse its motion? par • 2. A particle moves in a straight line such that for a short time its velocity is defined by V = ( 4t3 + 3t2 seconds. Determine its position and acceleration when t = 3 s; 2t) ft/s, where t is in %3D %3D he when t = 0, S = 0 %3D e pa he particle for wertical disola reach the ground tance that the paticle travel haght of the paratle, he t lury paricle when the bonzonl distence i 70 m dislmce whn the hayht uf the paricle is %23
A particle travels in a vertical path according to the relation y= 20+ sin2t + 3 cost where y is in centimeters and t is in seconds. Determine (a) the position, velocity, and acceleration of the particle when t = 3 s, (b) the maximum velocity and acceleration of the particle. 35- 30+ 25- 20+ 15+ 10+ 5+ -4 -3 -2 10- 15-
The velocity of a particle moving in a straight line is decreasing at the rate of 3 m/s per meter of displacement at an instant when the velocity is 10 m/s. Determine the acceleration a if the particle at instant. Ans. a = - 30 m/s?
Question 2: The applied force P causes block B to accelerate at ab = 5 Xb 0.25x ft/s², where x, is the position of block B measured from fixed point D. Initially, x, = 0.5 ft and the blocks are at rest. When x = 3 ft, find: a) The velocity and acceleration of B relative to A b) The absolute velocity of point C on the cable CA D- For each answer, report whether the direction is to the right or the left. -
1- A particle moves along the x axis. Its position varies with time according to the expression x=-41+ 2f where x is in meters and t is in seconds. The position-time graph for this motion is shown in Figure. Note that the particle moves in the negative x direction for the first second of motion, is momentarily at rest at the moment 1 = 1 s, and moves in the positive x direction at times /> 1 s. (A) Determine the displacement of the particle in the time intervals t=0 to 1=1 s and t= 1 s to / = 3 s. B) Calculate the average velocity during these two-time intervals C) determine the instantaneous velocity and instantaneous speed at t= 0.5 s. x(m) Slope = 4 m/s 10 00 8 9 10 O Slope =-2 m/s 1 2 015 t(s)
A particle travels along a straight-line path such that in 4 s it moves from an initial position S_C=-8 m to a position S_Bd=+3 m. Then in another 5 s it moves from S_B to S_C=-6 m. Determine the particle's average velocity and average speed during the 9-s time interval.
1. When displacement S is given in terms of time t, if S = 2t3 + t? ; meter, determine (a) the velocity when t = 10 sec. (b) the acceleration when t = 5 sec.
Q3 A-A race car accelerates uniformly from 18.5 m's to 46.1 m's in 247 seconds. Determine the acceleration of the car and the distance traveled. B-A feather is dropped from rest on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s. Determine the time for the feather to fall to the surface of the moon.