The acceleration of a particle is defined as a = 9 – 3t2. The particle starts at t = 0 with v = 0 and x =5 m. Determine: 1. The time when the velocity is again zero. 2. The position and velocity when t = 4 s Select one: A. t 3; x(4) = 13 m and v(4) =-28 m/s %3D %3D B. t = 1; x(4) = 13 m and v(4) = -28 m/s %3D C. t 0; x(4) = 13 m and v(4) -28 m/s %3D D. t = 3; x(4) = 13 m and v(4) = 28 m/s %3D
The acceleration of a particle is defined as a = 9 – 3t2. The particle starts at t = 0 with v = 0 and x =5 m. Determine: 1. The time when the velocity is again zero. 2. The position and velocity when t = 4 s Select one: A. t 3; x(4) = 13 m and v(4) =-28 m/s %3D %3D B. t = 1; x(4) = 13 m and v(4) = -28 m/s %3D C. t 0; x(4) = 13 m and v(4) -28 m/s %3D D. t = 3; x(4) = 13 m and v(4) = 28 m/s %3D
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![The acceleration of a particle is defined as
a = 9 – 3t2. The particle starts at t 0 with
v = 0 and x = 5 m. Determine:
1.
The time when the velocity is again
zero.
2.
The position and velocity when t = 4 s
Select one:
A. t = 3; x(4) = 13 m and v(4) = -28 m/s
%3D
B. t = 1; x(4) = 13 m and v(4) = -28 m/s
%3D
!i!
C. t = 0; x(4) = 13 m and v(4) = -28 m/s
%3D
%3D
D. t = 3; x(4) = 13 m and v(4) = 28 m/s
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd4621452-8697-4b3d-8fa7-50dd9ff4b561%2F752f9b75-9c99-4343-9c0e-9cc7da9862a9%2Fkeje2en_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The acceleration of a particle is defined as
a = 9 – 3t2. The particle starts at t 0 with
v = 0 and x = 5 m. Determine:
1.
The time when the velocity is again
zero.
2.
The position and velocity when t = 4 s
Select one:
A. t = 3; x(4) = 13 m and v(4) = -28 m/s
%3D
B. t = 1; x(4) = 13 m and v(4) = -28 m/s
%3D
!i!
C. t = 0; x(4) = 13 m and v(4) = -28 m/s
%3D
%3D
D. t = 3; x(4) = 13 m and v(4) = 28 m/s
%3D
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