Q24. The acceleration of a particle undergoing rectilinear, erratic motion has acceleration-time (a-t) function shown in the image below. The equation for 0

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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**Question 24:**

The acceleration of a particle undergoing rectilinear, erratic motion is represented by the acceleration-time (\(a-t\)) function shown in the image below. For \(0 < t < 3\) seconds (the curved portion), the equation is \(a = C \cdot t^2 \, \text{m/s}^2\), where \(C\) is a constant, and \(t\) is the time in seconds. If the constant \(C\) is 0.1, and the initial velocity \(v_0 = 0\) at time \(t = 0\), determine the particle's velocity when \(t = 5.4\) seconds. Please pay attention: the numbers may change since they are randomized. Your answer must include three decimal places and proper SI unit.

**Graph Explanation:**

The graph depicts the acceleration (\(a\) in m/s²) versus time (\(t\) in seconds). It shows:
- A rising curve from \(t = 0\) to \(t = 3\) seconds, where acceleration is increasing.
- Beyond \(t = 3\) seconds, the graph shows a downward-sloping line till \(t = 6\) seconds, indicating decreasing acceleration.

The graph implies that for \(0 < t < 3\) seconds, the acceleration follows a quadratic relation \(a = C \cdot t^2\).

**Your Answer:**

| Answer      | Units |
|-------------|-------|
| [Numeric Answer] | [m/s] |
Transcribed Image Text:**Question 24:** The acceleration of a particle undergoing rectilinear, erratic motion is represented by the acceleration-time (\(a-t\)) function shown in the image below. For \(0 < t < 3\) seconds (the curved portion), the equation is \(a = C \cdot t^2 \, \text{m/s}^2\), where \(C\) is a constant, and \(t\) is the time in seconds. If the constant \(C\) is 0.1, and the initial velocity \(v_0 = 0\) at time \(t = 0\), determine the particle's velocity when \(t = 5.4\) seconds. Please pay attention: the numbers may change since they are randomized. Your answer must include three decimal places and proper SI unit. **Graph Explanation:** The graph depicts the acceleration (\(a\) in m/s²) versus time (\(t\) in seconds). It shows: - A rising curve from \(t = 0\) to \(t = 3\) seconds, where acceleration is increasing. - Beyond \(t = 3\) seconds, the graph shows a downward-sloping line till \(t = 6\) seconds, indicating decreasing acceleration. The graph implies that for \(0 < t < 3\) seconds, the acceleration follows a quadratic relation \(a = C \cdot t^2\). **Your Answer:** | Answer | Units | |-------------|-------| | [Numeric Answer] | [m/s] |
Expert Solution
Step 1

Given data 

For 0 to 3 sec 

Acceleration = C.t2

Where C= 0.1 

Initial velocity= 0

Find the velocity at t= 5.4 sec

 

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